Submission #441350

#TimeUsernameProblemLanguageResultExecution timeMemory
441350zaneyuFurniture (JOI20_furniture)C++14
5 / 100
5092 ms980 KiB
/*input 2 3 0 0 1 0 0 0 2 1 2 2 2 */ #include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; typedef tree<int,null_type,less_equal<int>,rb_tree_tag,tree_order_statistics_node_update> indexed_set; #pragma GCC target("avx,avx2,fma") #pragma GCC optimize("Ofast,unroll-loops") //order_of_key #of elements less than x // find_by_order kth element using ll=long long; using ld=long double; using pii=pair<int,int>; #define f first #define s second #define pb push_back #define REP(i,n) for(ll i=0;i<n;i++) #define REP1(i,n) for(ll i=1;i<=n;i++) #define FILL(n,x) memset(n,x,sizeof(n)) #define ALL(_a) _a.begin(),_a.end() #define sz(x) (int)x.size() #define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end())))) const ll INF64=1e18+1; const int INF=0x3f3f3f3f; int MOD=1e9+7; const ld PI=acos(-1); const ld eps=1e-3; #define lowb(x) x&(-x) #define MNTO(x,y) x=min(x,(__typeof__(x))y) #define MXTO(x,y) x=max(x,(__typeof__(x))y) inline ll mult(ll a,ll b){ if(a>=MOD) a%=MOD; if(b>=MOD) b%=MOD; return (a*b)%MOD; } inline ll mypow(ll a,ll b){ if(b<=0) return 1; ll res=1LL; while(b){ if(b&1) res=mult(res,a); a=mult(a,a); b>>=1; } return res; } const int maxn=1e3+5; const int maxlg=__lg(maxn)+2; int arr[maxn][maxn]; bool vis[maxn][maxn]; int32_t main(){ ios::sync_with_stdio(false),cin.tie(0); int n,m; cin>>n>>m; REP(i,n) REP(j,m){ cin>>arr[i][j]; } int q; cin>>q; while(q--){ int x,y; cin>>x>>y; --x,--y; REP(i,n) REP(j,m) vis[i][j]=0; arr[x][y]=1; queue<pii> q; q.push({0,0}); vis[0][0]=1; while(!q.empty()){ pii z=q.front(); q.pop(); if(z.f<n-1 and !arr[z.f+1][z.s] and !vis[z.f+1][z.s]) vis[z.f+1][z.s]=1,q.push({z.f+1,z.s}); if(z.s<m-1 and !arr[z.f][z.s+1] and !vis[z.f][z.s+1]) vis[z.f][z.s+1]=1,q.push({z.f,z.s+1}); } cout<<vis[n-1][m-1]<<'\n'; if(!vis[n-1][m-1]) arr[x][y]=0; } }
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