oj.uz

답안 #440805

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
440805 2021-07-03T08:30:16 Z sinamhdv Pipes (CEOI15_pipes) C++11
40 / 100
 5000 ms 65536 KB 
// CEOI15_pipes
// 1st solution (reading input twice)
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int mod = 1000 * 1000 * 1000 + 7;
const int INF = 1e9 + 100;
const ll LINF = 1e18 + 100;

#ifdef DEBUG
#define dbg(x) cout << #x << " = " << (x) << endl << flush;
#define dbgr(s, f) { cout << #s << ": "; for (auto _ = (s); _ != (f); _++) cout << *_ << ' '; cout << endl << flush; }
#else
#define dbg(x) ;
#define dbgr(s, f) ;
#endif
#define FOR(i, a, b) for (int i = (a); i < (int)(b); i++)
#define fast_io ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define mp make_pair
#define fr first
#define sc second
#define endl '\n'

#define MAXN 100100
#define LOGN 19

int n, m;
set<int> intree;
vector<int> adj[MAXN];
int lpar[LOGN][MAXN], h[MAXN];
bool mark[MAXN];
int val[MAXN];

int dpar[MAXN];
int getroot(int x)
{
	return dpar[x] == x ? x : dpar[x] = getroot(dpar[x]);
}
bool merge(int x, int y)
{
	x = getroot(x);
	y = getroot(y);
	if (x == y) return false;
	dpar[x] = y;
	return true;
}

void dfs1(int v)
{
	mark[v] = true;
	for (int u : adj[v]) if (!mark[u])
	{
		lpar[0][u] = v;
		h[u] = h[v] + 1;
		dfs1(u);
	}
}

void dfs2(int v)
{
	mark[v] = true;
	for (int u : adj[v]) if (!mark[u]) dfs2(u), val[v] += val[u];
	if (lpar[0][v] && val[v] == 0) cout << v << ' ' << lpar[0][v] << endl;
}

int getlca(int x, int y)
{
	if (h[y] < h[x]) swap(x, y);
	FOR(i, 0, LOGN) if ((h[y] - h[x]) >> i & 1) y = lpar[i][y];
	if (x == y) return x;
	for (int i = LOGN - 1; i >= 0; i--) if (lpar[i][x] != lpar[i][y])
	{
		x = lpar[i][x];
		y = lpar[i][y];
	}
	return lpar[0][x];
}

int32_t main(void)
{
	fast_io;
	cin >> n >> m;

	iota(dpar, dpar + n + 10, 0);

	FOR(i, 0, m)
	{
		int x, y;
		cin >> x >> y;
		if (merge(x, y))
		{
			intree.insert(i);
			adj[x].pb(y);
			adj[y].pb(x);
		}
	}

	FOR(i, 1, n + 1) if (!mark[i]) dfs1(i);

	FOR(i, 1, LOGN) FOR(j, 1, n + 1) lpar[i][j] = lpar[i - 1][lpar[i - 1][j]];

	cin.seekg(0);
	cin >> n >> m;
	FOR(i, 0, m)
	{
		int x, y;
		cin >> x >> y;
		if (intree.find(i) != intree.end()) continue;
		val[x]++;
		val[y]++;
		val[getlca(x, y)] -= 2;
	}

	memset(mark, 0, sizeof(mark));
	FOR(i, 1, n + 1) if (!mark[i]) dfs2(i);

	return 0;
}

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2764 KB Output is correct
2 Correct 3 ms 2816 KB Output is correct

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 11 ms 3640 KB Output is correct
2 Correct 11 ms 3596 KB Output is correct

Subtask #3
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 439 ms 8832 KB Output is correct
2 Correct 367 ms 8668 KB Output is correct

Subtask #4
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 772 ms 13968 KB Output is correct
2 Correct 934 ms 15676 KB Output is correct

Subtask #5
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 1394 ms 22868 KB Memory limit exceeded
2 Halted 0 ms 0 KB -

Subtask #6
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 2648 ms 35024 KB Memory limit exceeded
2 Halted 0 ms 0 KB -

Subtask #7
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 4493 ms 49244 KB Memory limit exceeded
2 Halted 0 ms 0 KB -

Subtask #8
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 5029 ms 62972 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #9
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 5068 ms 65536 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #10
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 5064 ms 65536 KB Time limit exceeded
2 Halted 0 ms 0 KB -