이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// Knapsack DP is harder than FFT.
#include<bits/stdc++.h>
using namespace std;
typedef long long ll; typedef pair<int,int> pii; typedef pair<ll,ll> pll;
#define ff first
#define ss second
#define pb emplace_back
#define AI(x) begin(x),end(x)
template<class I>bool chmax(I&a,I b){return a<b?(a=b,true):false;}
template<class I>bool chmin(I&a,I b){return b<a?(a=b,true):false;}
#ifdef OWO
#define debug(args...) SDF(#args, args)
#define OIU(args...) ostream& operator<<(ostream&O,args)
#define LKJ(S,B,E,F) template<class...T>OIU(S<T...>s){O<<B;int c=0;for(auto i:s)O<<(c++?", ":"")<<F;return O<<E;}
LKJ(vector,'[',']',i)LKJ(deque,'[',']',i)LKJ(set,'{','}',i)LKJ(multiset,'{','}',i)LKJ(unordered_set,'{','}',i)LKJ(map,'{','}',i.ff<<':'<<i.ss)LKJ(unordered_map,'{','}',i.ff<<':'<<i.ss)
template<class...T>void SDF(const char* s,T...a){int c=sizeof...(T);if(!c){cerr<<"\033[1;32mvoid\033[0m\n";return;}(cerr<<"\033[1;32m("<<s<<") = (",...,(cerr<<a<<(--c?", ":")\033[0m\n")));}
template<class T,size_t N>OIU(array<T,N>a){return O<<vector<T>(AI(a));}template<class...T>OIU(pair<T...>p){return O<<'('<<p.ff<<','<<p.ss<<')';}template<class...T>OIU(tuple<T...>t){return O<<'(',apply([&O](T...s){int c=0;(...,(O<<(c++?", ":"")<<s));},t),O<<')';}
#else
#pragma GCC optimize("Ofast")
#define debug(...) ((void)0)
#endif
const int kN = 200002;
int n, t;
int tot = 0;
bool occ[kN];
pii seg[kN];
void insert(int l, int r){
int id = ++tot;
seg[id] = pii(l, r);
occ[id] = true;
}
void remove(int id){
occ[id] = false;
}
int query(int ql, int qr, int k){
if(qr - ql + 1 < k) return 0;
int ans = 0;
for(int i = 1; i <= tot; ++i){
if(!occ[i]) continue;
auto [l, r] = seg[i];
//if(r >= qr) ans += (qr - l + 1 >= k);
//else ans += (r - ql + 1 >= k);
if(min(r, qr) - max(l, ql) + 1 >= k) ++ans;
}
return ans;
}
signed main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin >> n >> t;
assert(n <= 10000);
int lastans = 0;
for(int cmd, a, b, k, id, i = 0; i < n; ++i){
cin >> cmd;
if(cmd == 1){
cin >> a >> b;
int l = (a ^ (lastans * t));
int r = (b ^ (lastans * t));
if(l > r) swap(l, r);
insert(l, r);
} else if(cmd == 2){
cin >> id;
remove(id);
} else if(cmd == 3){
cin >> a >> b >> k;
int l = (a ^ (lastans * t));
int r = (b ^ (lastans * t));
if(l > r) swap(l, r);
lastans = query(l, r, k);
cout << lastans << '\n';
}
}
return 0;
}
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