이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "garden.h"
#include "gardenlib.h"
#define inf 1000000007
#define mod 1000000007
#define rnd() rand_num()
#define bigrnd() dis(rand_num)
//#pragma GCC optimize("Ofast","inline","-ffast-math")
//#pragma GCC target("avx,sse2,sse3,sse4,mmx")
//#define int long long
using namespace std;
unsigned sed=std::chrono::system_clock::now().time_since_epoch().count();
mt19937 rand_num(sed);
uniform_int_distribution<long long> dis(0,inf);
template <typename T> void read(T &x){
x=0;char ch=getchar();int fh=1;
while (ch<'0'||ch>'9'){if (ch=='-')fh=-1;ch=getchar();}
while (ch>='0'&&ch<='9')x=x*10+ch-'0',ch=getchar();
x*=fh;
}
template <typename T> void write(T x) {
if (x<0) x=-x,putchar('-');
if (x>9) write(x/10);
putchar(x%10+'0');
}
template <typename T> void writeln(T x) {
write(x);
puts("");
}
int len[2]={inf,inf},color,col[150005][2];
int dist[150005][2][2];
bool vis[150005][2];
vector<int> g[150005];
vector<pair<int,int>> out[150005][2];
void buildgraph(int node,int cur)
{
if(vis[node][cur]) return;
vis[node][cur]=1;
int nnode,nxt;
if(cur==0) nnode=g[node][0];
else nnode=(g[node].size()>1?g[node][1]:g[node][0]);
if(g[nnode][0]==node) nxt=1;
else nxt=0;
buildgraph(nnode,nxt);
out[nnode][nxt].push_back(make_pair(node,cur));
}
void dfs(int node,int w,int d,int s)
{
if(col[node][w]==color)
{
if(w==s) len[s]=d;
return;
}
col[node][w]=color;
dist[node][w][s]=d;
for(pair<int,int> i:out[node][w])
dfs(i.first,i.second,d+1,s);
}
void count_routes(int N,int M,int P,int R[][2],int Q,int G[])
{
for(int i=0;i<M;++i)
{
g[R[i][0]].push_back(R[i][1]);
g[R[i][1]].push_back(R[i][0]);
}
for(int i=0;i<N;++i)
for(int j=0;j<2;++j)
if(!vis[i][j])
buildgraph(i,j);
for(int i=0;i<N;++i)
for(int j=0;j<2;++j)
for(int k=0;k<2;++k)
dist[i][j][k]=inf;
color++;
dfs(P,0,0,0);
color++;
dfs(P,1,0,1);
for(int i=0;i<Q;++i)
{
int ans=0;
for(int j=0;j<N;++j)
{
if(G[i]>=dist[j][0][0]&&(G[i]-dist[j][0][0])%len[0]==0) ans++;
if(G[i]>=dist[j][0][1]&&(G[i]-dist[j][0][1])%len[1]==0) ans++;
}
answer(ans);
}
}
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