Submission #438534

#	Time	Username	Problem	Language	Result	Execution time	Memory
438534		adamjinwei	Detecting Molecules (IOI16_molecules)	C++14	9 / 100	1 ms	292 KiB

molecules

#include <bits/stdc++.h>
#include "molecules.h"
#define inf 1000000007
#define mod 1000000007
#define rnd() rand_num()
#define bigrnd() dis(rand_num)
//#pragma GCC optimize("Ofast","inline","-ffast-math")
//#pragma GCC target("avx,sse2,sse3,sse4,mmx")
//#define int long long
using namespace std;
unsigned sed=std::chrono::system_clock::now().time_since_epoch().count();
mt19937 rand_num(sed);
uniform_int_distribution<long long> dis(0,inf);
template <typename T> void read(T &x){
	x=0;char ch=getchar();int fh=1;
	while (ch<'0'||ch>'9'){if (ch=='-')fh=-1;ch=getchar();}
	while (ch>='0'&&ch<='9')x=x*10+ch-'0',ch=getchar();
	x*=fh;
}
template <typename T> void write(T x) {
	if (x<0) x=-x,putchar('-');
	if (x>9) write(x/10);
	putchar(x%10+'0');
}
template <typename T> void writeln(T x) {
	write(x);
	puts("");
}
int n;
pair<int,int> p[200005];
vector<int> find_subset(int L,int R,vector<int> W)
{
	n=W.size();
	for(int i=1;i<=n;++i)
	{
		p[i].first=W[i-1];
		p[i].second=i-1;
	}
	sort(p+1,p+n+1);
	for(int i=1;i<=n;++i)
		if(L<=p[i].first&&p[i].first<=R)
		{
			vector<int> ans;
			ans.push_back(p[i].second);
			return ans;
		}
	int sum=0;
	for(int i=1;i<=n-1;++i)
	{
		sum+=p[i].first;
		if(sum<L)
		{
			sum-=p[1].first;
			sum+=p[n].first;
			if(sum>=L&&sum<=R)
			{
				vector<int> ans;
				for(int j=2;j<=i;++j)
					ans.push_back(p[j].second);
				ans.push_back(p[n].second);
				return ans;
			}
			sum+=p[1].first;
			sum-=p[n].first;
		}
		else if(sum>=L&&sum<=R)
		{
			vector<int> ans;
			for(int j=1;j<=i;++j)
				ans.push_back(p[j].second);
			return ans;
		}
	}
	sum+=p[n].first;
	if(sum>=L&&sum<=R)
	{
		vector<int> ans;
		for(int j=1;j<=n;++j)
			ans.push_back(p[j].second);
		return ans;
	}
	sum=0;
	for(int i=n;i>=2;--i)
	{
		sum+=p[i].first;
		if(sum>R)
		{
			sum-=p[n].first;
			sum+=p[1].first;
			if(sum>=L&&sum<=R)
			{
				vector<int> ans;
				for(int j=i;j<=n-1;++j)
					ans.push_back(p[j].second);
				ans.push_back(p[1].second);
				return ans;
			}
			sum+=p[n].first;
			sum-=p[1].first;
		}
		else if(sum>=L&&sum<=R)
		{
			vector<int> ans;
			for(int j=1;j<=i;++j)
				ans.push_back(p[j].second);
			return ans;
		}
	}
	vector<int> ans;
	return ans;
}

• Subtask 1: 9 / 9
• Subtask 2: 0 / 10
• Subtask 3: 0 / 12
• Subtask 4: 0 / 15
• Subtask 5: 0 / 23
• Subtask 6: 0 / 31