제출 #438420

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
438420		mango_lassi	던전 (IOI21_dungeons)	C++17	11 / 100	7100 ms	248500 KiB

dungeons

#include "dungeons.h"
#include <bits/stdc++.h>
using namespace std;
using ll = long long;

const ll INF = 1e9 + 7;
const int N = 4 * (int)1e5;
const int H = 6; // 24 / 4
pair<int, ll> jmp[N + 1][H][H];
ll str[N + 1];
ll bns[N + 1];
int wt[N + 1];
int lt[N + 1];
int n;

pair<int, ll> advance(pair<int, ll> cur) {
	if (str[cur.first] > cur.second) return {lt[cur.first], bns[cur.first] + cur.second};
	else return {wt[cur.first], str[cur.first] + cur.second};
}

void init(int n_, vector<int> s, vector<int> p, vector<int> w, vector<int> l) {
	n = n_;
	for (int i = 0; i < n; ++i) str[i] = s[i];
	for (int i = 0; i < n; ++i) bns[i] = p[i];
	for (int i = 0; i < n; ++i) wt[i] = w[i];
	for (int i = 0; i < n; ++i) lt[i] = l[i];
	str[n] = 0;
	bns[n] = 0;
	wt[n] = n;
	lt[n] = n;
	
	for (int a = 0; a < H; ++a) {
		ll lo = 1 << (4 * a);
		ll hi = 1 << (4 * (a + 1));
		for (int i = 0; i <= n; ++i) {
			if ((lo <= str[i] && str[i] < hi) || i == n) {
				jmp[i][a][0] = {i, INF};
			} else if (str[i] < lo) {
				jmp[i][a][0] = {wt[i], str[i]};
			} else {
				jmp[i][a][0] = {lt[i], bns[i]};
			}
		}
		for (int b = 1; b < H; ++b) {
			for (int i = 0; i <= n; ++i) {
				pair<int, ll> res = {i, 0ll};
				for (int it = 0; it < 16; ++it) {
					res.second += jmp[res.first][a][b - 1].second;
					res.first = jmp[res.first][a][b - 1].first;
				}
				jmp[i][a][b] = res;
			}
		}
	}
}

long long simulate(int start_i, int ini_pwr) {
	pair<int, ll> state = {start_i, (ll)ini_pwr};
	for (int a = 0; a < H; ++a) {
		ll lo = 1 << (4 * a);
		ll hi = 1 << (4 * (a + 1));
		while(state.first != n && lo <= state.second && state.second < hi) {
			for (int b = H-1; b >= 0; --b) {
				while(state.second + jmp[state.first][a][b].second < hi) {
					state.second += jmp[state.first][a][b].second;
					state.first = jmp[state.first][a][b].first;
				}
			}
			state = advance(state); // either fight against opponent in same strength bracket, or break out of strength bracket
		}
	}
	while(state.first != n) state = advance(state);
	return state.second;
}

• Subtask 1: 11 / 11
• Subtask 2: 0 / 26
• Subtask 3: 0 / 13
• Subtask 4: 0 / 12
• Subtask 5: 0 / 27
• Subtask 6: 0 / 11