oj.uz

답안 #437507

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
437507 2021-06-26T11:58:09 Z sinamhdv Pipes (CEOI15_pipes) C++11
40 / 100
 5000 ms 65536 KB 
// CEOI15_pipes
// 1st solution (reading input twice)
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int mod = 1000 * 1000 * 1000 + 7;
const int INF = 1e9 + 100;
const ll LINF = 1e18 + 100;

#ifdef DEBUG
#define dbg(x) cout << #x << " = " << (x) << endl << flush;
#define dbgr(s, f) { cout << #s << ": "; for (auto _ = (s); _ != (f); _++) cout << *_ << ' '; cout << endl << flush; }
#else
#define dbg(x) ;
#define dbgr(s, f) ;
#endif
#define FOR(i, a, b) for (int i = (a); i < (int)(b); i++)
#define fast_io ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define mp make_pair
#define fr first
#define sc second
#define endl '\n'

#define MAXN 100100
#define LOGN 22

int n, m;
unordered_set<int> intree;
vector<int> adj[MAXN];
int lpar[LOGN][MAXN], h[MAXN];;
vector<int> dfs_ord;
bool mark[MAXN];
int val[MAXN];

int dpar[MAXN];
int getroot(int x)
{
	return dpar[x] == x ? x : dpar[x] = getroot(dpar[x]);
}
bool merge(int x, int y)
{
	x = getroot(x);
	y = getroot(y);
	if (x == y) return false;
	dpar[x] = y;
	return true;
}

void dfs(int v)
{
	mark[v] = true;
	for (int u : adj[v]) if (!mark[u])
	{
		lpar[0][u] = v;
		h[u] = h[v] + 1;
		dfs(u);
	}
	dfs_ord.pb(v);
}

int getlca(int x, int y)
{
	if (h[y] < h[x]) swap(x, y);
	FOR(i, 0, LOGN) if ((h[y] - h[x]) >> i & 1) y = lpar[i][y];
	if (x == y) return x;
	for (int i = LOGN - 1; i >= 0; i--) if (lpar[i][x] != lpar[i][y])
	{
		x = lpar[i][x];
		y = lpar[i][y];
	}
	return lpar[0][x];
}

int32_t main(void)
{
	fast_io;
	cin >> n >> m;

	iota(dpar, dpar + n + 10, 0);

	FOR(i, 0, m)
	{
		int x, y;
		cin >> x >> y;
		if (merge(x, y))
		{
			intree.insert(i);
			adj[x].pb(y);
			adj[y].pb(x);
		}
	}

	FOR(i, 1, n + 1)
	{
		if (!mark[i])
		{
			dfs(i);
		}
	}

	FOR(i, 1, LOGN) FOR(j, 1, n + 1) lpar[i][j] = lpar[i - 1][lpar[i - 1][j]];

	cin.seekg(0);
	cin >> n >> m;
	FOR(i, 0, m)
	{
		int x, y;
		cin >> x >> y;
		if (intree.find(i) != intree.end()) continue;
		val[x]++;
		val[y]++;
		val[getlca(x, y)] -= 2;
	}

	for (int v : dfs_ord)
	{
		for (int u : adj[v]) if (u != lpar[0][v]) val[v] += val[u];
		if (val[v] == 0 && lpar[0][v]) cout << v << ' ' << lpar[0][v] << endl;
	}

	return 0;
}

Subtask #1
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2764 KB Output is correct
2 Correct 3 ms 2764 KB Output is correct

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 11 ms 3720 KB Output is correct
2 Correct 10 ms 3692 KB Output is correct

Subtask #3
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 388 ms 8812 KB Output is correct
2 Correct 330 ms 8744 KB Output is correct

Subtask #4
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 707 ms 14164 KB Output is correct
2 Correct 748 ms 15836 KB Output is correct

Subtask #5
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 1154 ms 23292 KB Memory limit exceeded
2 Halted 0 ms 0 KB -

Subtask #6
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 2194 ms 36240 KB Memory limit exceeded
2 Halted 0 ms 0 KB -

Subtask #7
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 3732 ms 50452 KB Memory limit exceeded
2 Halted 0 ms 0 KB -

Subtask #8
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 5050 ms 64820 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #9
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 5025 ms 65536 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #10
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 5032 ms 65536 KB Time limit exceeded
2 Halted 0 ms 0 KB -