이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cstring>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <vector>
using namespace std;
// BEGIN NO SAD
#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define trav(a, x) for(auto& a : x)
#define all(x) x.begin(), x.end()
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define lb lower_bound
#define ub upper_bound
typedef vector<int> vi;
#define f first
#define s second
// END NO SAD
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<vector<ll>> matrix;
void init(vector<array<int, 3>>& v) {
int n;
cin >> n;
v.resize(n);
for(auto& x: v) cin >> x[1] >> x[0] >> x[2];
sort(all(v));
}
const ll BAD = -1e18;
ll dp[100005];
void solve() {
vector<array<int, 3>> computers; // <clock rate, cores, price>
vector<array<int, 3>> jobs; // <clock rate, cores, price>
init(computers);
init(jobs);
fill(dp, dp + 100005, BAD);
dp[0] = 0;
ll ret = 0;
while(sz(jobs)) {
if(sz(computers) && computers.back()[0] >= jobs.back()[0]) {
auto x = computers.back(); computers.pop_back();
for(int i = 100000; i >= x[1]; i--) {
if(dp[i-x[1]] == BAD) continue;
dp[i] = max(dp[i], dp[i-x[1]] - x[2]);
}
}
else {
auto x = jobs.back(); jobs.pop_back();
for(int i = 0; i + x[1] <= 100000; i++) {
if(dp[i+x[1]] == BAD) continue;
ret = max(ret, dp[i] = max(dp[i], dp[i+x[1]] + x[2]));
}
}
}
cout << ret << "\n";
}
// what would chika do
// are there edge cases (N=1?)
// are array sizes proper (scaled by proper constant, for example 2* for koosaga tree)
// integer overflow?
// DS reset properly between test cases
// are you doing geometry in floating points
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL); cout.tie(NULL);
solve();
}
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