제출 #434161

#제출 시각아이디문제언어결과실행 시간메모리
434161krist7599555Jelly Flavours (IOI20_jelly)C++17
100 / 100
124 ms452 KiB
#include <algorithm> #include <cassert> #include <cstring> #include <vector> #include <numeric> #include <iostream> #include <tuple> typedef std::vector<int> Vec; typedef std::pair<int, int> Pii; #define rep(i,a,b) for(auto i = a; i != b; ++i) struct Data { int jelly_count, remain_b; Data(int cnt, int rem): jelly_count(cnt), remain_b(rem) {} Data increase_jelly_count() {return {jelly_count+1, remain_b};} Data buy_b(int cost) { return {jelly_count+1, remain_b - cost};} bool operator < (const Data& o) const { return std::tie(jelly_count, remain_b) < std::tie(o.jelly_count, o.remain_b); } }; int find_maximum_unique(int x_total, int y_total, std::vector<int> an, std::vector<int> bn) { assert(an.size() == bn.size() and an.size() <= 2e3); std::vector<Data> dp(x_total+1, Data(0, 0)); // dp[i] = how many jelly count can do when `remain x` == i dp[x_total] = Data(0, y_total); // dp[remain_a=max_x] = { jelly_count: 0, remain_b: max_b } std::vector<int> ord(an.size()); // ord = sorted index by `b` std::iota(ord.begin(), ord.end(), 0); // 0 1 2 3 4 5 6 7 std::sort(ord.begin(), ord.end(), [&](int u, int v){ return bn[u] < bn[v]; }); for (int i : ord) { int curr_a = an[i]; // a = ? ? ? ? ? int curr_b = bn[i]; // b = 1 2 3 4 5 for(int remain_a = 0; remain_a <= x_total; ++remain_a) { dp[remain_a] = std::max({ // case 1: not neither buy from `a` or `b` dp[remain_a], // case 2: buy from `b` greedy // same dp[remain_a] but reduce remain_b curr_b <= dp[remain_a].remain_b ? dp[remain_a].buy_b(curr_b) // greedy by `b` if possible : dp[remain_a], // case 3: buy from `a` dynamic programing // reduce from `remain_a + curr_a` to `remain_a` curr_a + remain_a <= x_total ? dp[remain_a + curr_a].increase_jelly_count() // dynamic programming on `a` : dp[remain_a] }); } } return std::max_element(dp.begin(), dp.end())->jelly_count; } #ifdef KRIST_LOCAL inline int input() { int i; std::cin >> i; return i; } int main() { assert(2 == find_maximum_unique(2, 3, Vec({2, 1, 4}), Vec({2, 3, 2}))); assert(4 == find_maximum_unique(6, 12, Vec({5, 1, 5, 6, 3}), Vec({3, 5, 4, 6, 7}))); } #endif
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