이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define ld long double
#define pii pair<int, int>
#define pll pair<ll, ll>
#define vt vector
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define sz(x) (int) (x).size()
#pragma GCC optimize ("O3")
#pragma GCC optimize ("O2")
#define F first
#define S second
//#define endl '\n'
//#define int long long
using namespace std;
ll delivery(int N, int K, int L, int p[])
{
if (K == 1)
{
ll ans = 0;
for(int i = 0; i < N; i++) ans += 2 * min(p[i], L - p[i]);
return ans;
}
vt<pii> v;
for(int i = 0; i < N; i++) v.pb({p[i], i});
sort(all(v));
vt<int> order(N);
for(int i = 0; i < N; i++) order[i] = v[i].S;
ll dp[N][K + 1];
dp[0][K] = 2ll * min(p[order[0]], L - p[order[0]]);
for(int i = K - 1; i >= 0; i--)
dp[0][i] = min(p[order[0]], L - p[order[0]]);
for(int i = 1; i < N; i++)
{
ll tmp = (L - max(p[order[i]], p[order[i - 1]]));
tmp += min(p[order[i]], p[order[i - 1]]);
ll dist = min((ll) abs(p[order[i]] - p[order[i - 1]]), tmp);
dp[i][K] = dp[i - 1][1] + dist + min(p[order[i]], L - p[order[i]]);
dp[i][K - 1] = dp[i - 1][K] + min(p[order[i]], L - p[order[i]]);
for(int j = K - 2; j >= 0; j--)
dp[i][j] = dp[i - 1][j + 1] + dist;
}
ll mn = LLONG_MAX;
mn = dp[N - 1][0];
//for(int i = 0; i <= K; i++)
//{
//cout << dp[N - 1][i] << " ";
//mn = min(mn, dp[N - 1][i]);
//}
//cout << endl;
mn += min(p[order[N - 1]], L - p[order[N - 1]]);
/*
cout << mn << endl;
for(int i = K; i >= 0; i--)
{
for(int j = 0; j < N; j++) cout << dp[j][i] << " ";
cout << endl;
}
cout << endl;
*/
//for(int x : order) cout << p[x] << " ";
//cout << endl;
return mn;
}
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