제출 #433540

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
433540		Kevin_Zhang_TW	카멜레온의 사랑 (JOI20_chameleon)	C++17	40 / 100	27 ms	384 KiB

chameleon

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define pb emplace_back
#define AI(i) begin(i), end(i)
template<class T> bool chmin(T &a, T b) { return b < a && (a = b, true); }
template<class T> bool chmax(T &a, T b) { return a < b && (a = b, true); }
#ifdef KEV
#define DE(args...) kout("[ " + string(#args) + " ] = ", args)
void kout() { cerr << endl; }
template<class T, class ...U> void kout(T a, U ...b) { cerr << a << ' ', kout(b...); }
template<class T> void debug(T l, T r) { while (l != r) cerr << *l << " \n"[next(l)==r], ++l; }
#else
#define DE(...) 0
#define debug(...) 0
#endif
#include "chameleon.h"
#include <vector>

namespace {

const int MAX_N = 1010;
int qry(vector<int> p) { for (int &i : p) ++i; return Query(p); }

int n, love[MAX_N];
vector<int> edge[MAX_N];
void ans(int a, int b) { ++a, ++b; if (a > b) return; Answer(a, b); }

}


void Solve(int N) {
	n = N;
	fill(love, love + n + n, -1);

	for (int i = 0;i < n + n;++i) for (int j = i+1;j < n+n;++j)
		if (qry({i, j}) == 1)
			edge[i].pb(j), edge[j].pb(i);

	for (int i = 0;i < n + n;++i) {
		assert(edge[i].size() == 1 || edge[i].size() == 3);
		if (edge[i].size() == 1) continue;

		int cnt = 0;
		for (int j = 0;j < 3;++j) {
			vector<int> p {i};
			for (int k = 0;k < 3;++k) if (j != k) p.pb( edge[i][k] );
			if (qry(p) == 1) {
				love[ i ] = edge[i][j];
				++cnt;
			}
		}
		assert(cnt == 1);
	}

	for (int i = 0;i < n + n;++i) {
		for (int j = 0;j < edge[i].size();++j) {
			if (love[i] != edge[i][j] && love[ edge[i][j] ] != i)
				ans(i, edge[i][j]);
		}
	}

}

컴파일 시 표준 에러 (stderr) 메시지

chameleon.cpp: In function 'void Solve(int)':
chameleon.cpp:57:20: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   57 |   for (int j = 0;j < edge[i].size();++j) {
      |                  ~~^~~~~~~~~~~~~~~~

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• Subtask 2: 20 / 20
• Subtask 3: 20 / 20
• Subtask 4: 0 / 20
• Subtask 5: 0 / 36