Submission #432790

#	Time	Username	Problem	Language	Result	Execution time	Memory
432790		tengiz05	Miners (IOI07_miners)	C++17	100 / 100	386 ms	101184 KiB

miners

#include <bits/stdc++.h>
constexpr int N = 100000;
int dp[N][4][4][4][4];
int main() {
    std::ios::sync_with_stdio(false);
    std::cin.tie(nullptr);
    int n;
    std::cin >> n;
    std::string s;
    std::cin >> s;
    std::vector<int> a(n);
    for (int i = 0; i < n; i++) {
        a[i] = std::string("MFB").find(s[i]) + 1;
    }
    memset(dp, 190, sizeof dp);
    dp[0][0][a[0]][0][0] = 1;
    dp[0][0][0][0][a[0]] = 1;
    for (int p = 1; p < n; p++) {
        for (int i = 0; i < 4; i++)
            for (int j = 0; j < 4; j++)
                for (int I = 0; I < 4; I++)
                    for (int J = 0; J < 4; J++)
                        dp[p][i][j][I][J] = dp[p - 1][i][j][I][J];
        for (int i = 0; i < 4; i++) {
            for (int j = 0; j < 4; j++) {
                for (int I = 0; I < 4; I++) {
                    for (int J = 0; J < 4; J++) {
                        int cost;
                        if (i == 0 && j == 0) cost = 1;
                        else if (i == 0 || j == 0) cost = 1 + ((i ^ j) != a[p]);
                        else if (i == j && j == a[p]) cost = 1;
                        else if (i == j || j == a[p] || i == a[p]) cost = 2;
                        else cost = 3;
                        dp[p][j][a[p]][I][J] = std::max(dp[p][j][a[p]][I][J], dp[p - 1][i][j][I][J] + cost);
                        if (I == 0 && J == 0) cost = 1;
                        else if (I == 0 || J == 0) cost = 1 + ((I ^ J) != a[p]);
                        else if (I == J && J == a[p]) cost = 1;
                        else if (I == J || J == a[p] || I == a[p]) cost = 2;
                        else cost = 3;
                        dp[p][i][j][J][a[p]] = std::max(dp[p][i][j][J][a[p]], dp[p - 1][i][j][I][J] + cost);
                    }
                }
            }
        }
    }
    int ans = 0;
    for (int i = 0; i < 4; i++)
        for (int j = 0; j < 4; j++)
            for (int I = 0; I < 4; I++)
                for (int J = 0; J < 4; J++)
                    ans = std::max(ans, dp[n - 1][i][j][I][J]);
    std::cout << ans << "\n";
    return 0;
}

• Subtask 1: 9 / 9
• Subtask 2: 9 / 9
• Subtask 3: 9 / 9
• Subtask 4: 9 / 9
• Subtask 5: 9 / 9
• Subtask 6: 7 / 7
• Subtask 7: 8 / 8
• Subtask 8: 8 / 8
• Subtask 9: 8 / 8
• Subtask 10: 8 / 8
• Subtask 11: 8 / 8
• Subtask 12: 8 / 8