제출 #43226

#제출 시각아이디문제언어결과실행 시간메모리
43226szawinis전선 연결 (IOI17_wiring)C++14
100 / 100
155 ms76372 KiB
#include "wiring.h" #include <bits/stdc++.h> #define pos first #define col second using namespace std; using ll = long long; const int N = 2e5+1; const ll INF = 1e17; int n; vector<pair<int,int> > a; ll s[N], dp[N]; inline ll fl(int j, int k) { // j, k part of sum when i-k < k-j return dp[j] + s[j] - 2*s[k] - 1ll * (j-2*k) * a[k+1].pos; } inline ll fg(int j, int k) { return dp[j] + s[j] - 2*s[k] - 1ll * (j-2*k) * a[k].pos; } set<pair<ll,int> > stl, stg; // l: j <= 2*k-i, g: j > 2*k-i ll min_total_length(std::vector<int> r, std::vector<int> b) { n = r.size() + b.size(); for(int i = 0; i < r.size(); i++) a.emplace_back(r[i], 0); for(int i = 0; i < b.size(); i++) a.emplace_back(b[i], 1); a.emplace_back(INT_MIN, INT_MIN); sort(a.begin(), a.end()); for(int i = 1; i <= n; i++) s[i] = s[i-1] + a[i].pos; fill(dp+1, dp+n+1, INF); for(int i = 2, k = 0; i <= n; i++) { if(a[i].col != a[i-1].col) { k = i-1; stl.clear(); stg.clear(); for(int j = k-1; j >= 0 && a[j+1].col == a[k].col; j--) stl.emplace(fl(j, k), j); } if(!k) continue; // case segments completely disjoint if(!stl.empty()) dp[i] = min(stl.begin()->first + s[i] - 1ll * i * a[k+1].pos, dp[i]); if(!stg.empty()) dp[i] = min(stg.begin()->first + s[i] - 1ll * i * a[k].pos, dp[i]); if(!stl.empty()) { stl.erase(make_pair(fl(2*k-i, k), 2*k-i)); stg.emplace(make_pair(fg(2*k-i, k), 2*k-i)); } // special case: segments intersect at one node if(k-1 >= 1 && a[k-1].col == a[i].col) dp[i] = min(dp[k] + s[i] - s[k] - 1ll * (i-k) * a[k].pos, dp[i]); } return dp[n]; }

컴파일 시 표준 에러 (stderr) 메시지

wiring.cpp: In function 'll min_total_length(std::vector<int>, std::vector<int>)':
wiring.cpp:22:19: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
  for(int i = 0; i < r.size(); i++) a.emplace_back(r[i], 0);
                   ^
wiring.cpp:23:19: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
  for(int i = 0; i < b.size(); i++) a.emplace_back(b[i], 1);
                   ^
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