이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include"holiday.h"
using namespace std;
#define ll long long
#define pill pair<int,ll>
#define pi pair<int,int>
#define f first
#define s second
/***********************/
struct SegTree{
vector<pill> st;
int sz;
SegTree(int n){
sz = n;
st.assign(n*4, {0,0ll});
}
void updactive(int n, int l, int r, int ind, int val){
if(l == r){
st[n].f = val;
return;
}
int mid = (l + r)/2;
if(mid >= ind)
updactive(2*n+1, l, mid, ind, val);
else
updactive(2*n + 2, mid + 1, r, ind, val);
st[n].f = st[2*n+1].f + st[2*n+2].f;
}
void updval(int n, int l, int r, int ind, int val){
if(l == r){
st[n].s = val;
return;
}
int mid = (l + r)/2;
if(mid >= ind)
updval(2*n+1, l, mid, ind, val);
else
updval(2*n + 2, mid + 1, r, ind, val);
st[n].s = st[2*n+1].s + st[2*n+2].s;
}
void activate(int city,int val){
updactive(0,0,sz, city, 1);
updval(0,0,sz, city, val);
}
void deactivate(int city){
updactive(0,0,sz, city, 0);
updval(0,0,sz, city, 0);
}
int getfirst(int n, int l, int r, int val){
if(l == r) return l;
int mid = (l + r)/2;
if(st[2*n+1].f >= val )
return getfirst(2*n+1, l, mid, val);
return getfirst(2*n+ 2, mid + 1, r, val - st[2*n+1].f);
}
int getfirst(int val){
int target = st[0].f - val +1;
if(target <=0)
return 0;
return getfirst(0, 0, sz, target);
}
ll qrysum(int n, int l, int r, int s, int e){
if(s<= l and e >= r) return st[n].s;
ll ans = 0;
int mid = (l + r)/2;
if( mid >= s)
ans += qrysum(2*n+1, l, mid, s, e);
if(mid < e)
ans+=qrysum(2*n+2, mid + 1, r, s,e);
return ans;
}
ll getlargest(int rng){
if(rng <= 0) return 0;
int lower = getfirst(rng);
//cout << lower<<endl;
return qrysum(0, 0,sz, lower, sz );
}
};
long long int findMaxAttraction(int n, int start, int d, int attraction[]) {
ll ans = 0;
SegTree st(n);
//spend right days travelling
//visit day - right cities
vector<pi> cities(n);
for(int i =0; i<n; i++){
cities[i] = {attraction[i], i};
}
sort(cities.begin(), cities.end());
vector<int> inds(n);
for(int i= 0; i<n;i++)
inds[cities[i].s] = i;
for(int right = 0; right <n; right++){
st.activate(inds[right], attraction[right]);
//cout << right<<": "<< inds[right]<<", "<<st.getlargest(d - right)<<endl;
ans = max(ans, st.getlargest(d - right));
}
return ans;
}
/***********************/
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