제출 #432135

#제출 시각아이디문제언어결과실행 시간메모리
432135dreezy휴가 (IOI14_holiday)C++17
23 / 100
53 ms9108 KiB
#include <bits/stdc++.h> #include"holiday.h" using namespace std; #define ll long long #define pill pair<int,ll> #define pi pair<int,int> #define f first #define s second /***********************/ struct SegTree{ vector<pill> st; int sz; SegTree(int n){ sz = n; st.assign(n*4, {0,0ll}); } void updactive(int n, int l, int r, int ind, int val){ if(l == r){ st[n].f = val; return; } int mid = (l + r)/2; if(mid >= ind) updactive(2*n+1, l, mid, ind, val); else updactive(2*n + 2, mid + 1, r, ind, val); st[n].f = st[2*n+1].f + st[2*n+2].f; } void updval(int n, int l, int r, int ind, int val){ if(l == r){ st[n].s = val; return; } int mid = (l + r)/2; if(mid >= ind) updval(2*n+1, l, mid, ind, val); else updval(2*n + 2, mid + 1, r, ind, val); st[n].s = st[2*n+1].s + st[2*n+2].s; } void activate(int city,int val){ updactive(0,0,sz, city, 1); updval(0,0,sz, city, val); } void deactivate(int city){ updactive(0,0,sz, city, 0); updval(0,0,sz, city, 0); } int getfirst(int n, int l, int r, int val){ if(l == r) return l; int mid = (l + r)/2; if(st[2*n+1].f >= val ) return getfirst(2*n+1, l, mid, val); return getfirst(2*n+ 2, mid + 1, r, val - st[2*n+1].f); } int getfirst(int val){ int target = st[0].f - val +1; if(target <=0) return 0; return getfirst(0, 0, sz, target); } ll qrysum(int n, int l, int r, int s, int e){ if(s<= l and e >= r) return st[n].s; ll ans = 0; int mid = (l + r)/2; if( mid >= s) ans += qrysum(2*n+1, l, mid, s, e); if(mid < e) ans+=qrysum(2*n+2, mid + 1, r, s,e); return ans; } ll getlargest(int rng){ if(rng <= 0) return 0; int lower = getfirst(rng); //cout << lower<<endl; return qrysum(0, 0,sz, lower, sz ); } }; long long int findMaxAttraction(int n, int start, int d, int attraction[]) { ll ans = 0; SegTree st(n); //spend right days travelling //visit day - right cities vector<pi> cities(n); for(int i =0; i<n; i++){ cities[i] = {attraction[i], i}; } sort(cities.begin(), cities.end()); vector<int> inds(n); for(int i= 0; i<n;i++) inds[cities[i].s] = i; for(int right = 0; right <n; right++){ st.activate(inds[right], attraction[right]); //cout << right<<": "<< inds[right]<<", "<<st.getlargest(d - right)<<endl; ans = max(ans, st.getlargest(d - right)); } return ans; } /***********************/
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