이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <cstdio>
#include <iostream>
#include <algorithm>
#include <string>
#include <cstring>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <cmath>
#include <iomanip>
#include <cassert>
#include <bitset>
using namespace std;
typedef pair<long long, long long> P;
#define rep(i, n) for (int i=0; i<(n); i++)
#define all(c) (c).begin(), (c).end()
#define uniq(c) c.erase(unique(all(c)), (c).end())
#define index(xs, x) (int)(lower_bound(all(xs), x) - xs.begin())
#define _1 first
#define _2 second
#define pb push_back
#define INF 1145141919
#define MOD 1000000007
#define MAX_N (1<<17)
long long seg[MAX_N*2-1];
void update(int k, long long v) {
k += MAX_N-1;
seg[k] = max(seg[k], v);
while (k > 0) {
k = (k-1)/2;
seg[k] = max(seg[k*2+1], seg[k*2+2]);
}
}
long long query(int a, int b, int k=0, int l=0, int r=MAX_N) {
if (b <= l || r <= a) return 0;
if (a <= l && r <= b) return seg[k];
return max(query(a, b, k*2+1, l, (l+r)/2), query(a, b, k*2+2, (l+r)/2, r));
}
int N;
long long X[100000], A[100000], B[100000];
signed main() {
ios::sync_with_stdio(false); cin.tie(0);
cin >> N;
rep(i, N) cin >> X[i] >> A[i] >> B[i];
rep(i, N-1) A[i+1] += A[i];
rep(i, N-1) B[i+1] += B[i];
vector<long long> xs;
rep(i, N) xs.pb(B[i]-X[i]);
sort(all(xs)); uniq(xs);
long long m = 0;
for (int l=N-1; l>=0; l--) {
update(index(xs, B[l]-X[l]), A[l]);
long long border = (l>0?B[l-1]:0)-X[l];
long long v = query(index(xs, border), MAX_N);
if (v != 0) m = max(m, v - (l>0?A[l-1]:0));
}
cout << m << "\n";
return 0;
}
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