제출 #428704

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
428704		MarcoMeijer	식물 비교 (IOI20_plants)	C++14	17 / 100	4057 ms	58160 KiB

plants

#include "plants.h"
#include <bits/stdc++.h>
using namespace std;

// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e9
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
#define sz size()
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

const int N = (1<<20);

int n, k;
vi r;

struct Seg {
    ii mn[N*2]; int laz[N*2];
    void build(int p=1, int l=0, int r=N-1) {
        laz[p] = 0;
        if(l == r) {
            mn[p] = {0,l};
            return;
        }
        int m=(l+r)/2;
        build(p*2  ,l  ,m);
        build(p*2+1,m+1,r);
        mn[p] = min(mn[p*2],mn[p*2+1]);
    }
    void add(int p, int v) {
        laz[p] += v;
        mn[p] = {mn[p].fi+v, mn[p].se};
    }
    void pushDown(int p) {
        add(p*2  ,laz[p]);
        add(p*2+1,laz[p]);
        laz[p] = 0;
    }
    void add(int i, int j, int v, int p=1, int l=0, int r=N-1) {
        if(j < l || i > r) return;
        if(i <= l && j >= r) {
            add(p,v);
            return;
        }
        pushDown(p);
        int m=(l+r)/2;
        add(i,j,v,p*2,l,m);
        add(i,j,v,p*2+1,m+1,r);
        mn[p] = min(mn[p*2],mn[p*2+1]);
    }
    ii get(int i, int j, int p=1, int l=0, int r=N-1) {
        if(j < l || i > r) return {INF,INF};
        if(i <= l && j >= r) return mn[p];
        pushDown(p);
        int m=(l+r)/2;
        ii a = get(i,j,p*2,l,m);
        ii b = get(i,j,p*2+1,m+1,r);
        return min(a,b);
    }
    void addCircle(int i, int l, int v) {
        int j = i + l - 1;
        add(i,min(n-1,j),v);
        if(j > n-1)
            add(0,j-n,v);
    }
};

Seg seg1, seg2;

vi val;

void init(int k_, vi r_) {
    k = k_; r = r_;
    n = r.size();
    seg1.build(); seg2.build();
    RE(i,n) seg1.add(i,i,r[i]);
    RE(i,n) seg2.add(i,i,1);

    val.assign(n,0);
    REV(i,0,n) {
        while(true) {
            ii res = seg1.get(0,n-1);
            if(res.fi != 0)
                break;
            int j = res.se;
            seg1.add(j,j,INF);
            seg2.add(j,j,-1);
            seg2.addCircle((j+1)%n, k-1, 1);
        }

        ii res = seg2.get(0,n-1);
        int j = res.se;
        val[j] = i;
        seg2.add(j,j,INF);
        seg2.addCircle((j+1)%n, k-1, -1);
        seg1.addCircle((j-k+n+1)%n, k-1, -1);
    }
}

int compare_plants(int x, int y) {
    if(n <= 300) {
        bool re[2];
        RE(_,2) {
            int u = _ ? x : y;
            int v = _ ? y : x;
            seg1.build(); seg2.build();
            RE(i,n) seg1.add(i,i,r[i]);
            RE(i,n) seg2.add(i,i,1);

            re[_] = 0;

            val.assign(n,0);
            bool nRes = 1;
            REV(i,0,n) {
                while(true) {
                    ii res = seg1.get(0,n-1);
                    if(res.fi != 0)
                        break;
                    int j = res.se;
                    seg1.add(j,j,INF);
                    seg2.add(j,j,-1);
                    seg2.addCircle((j+1)%n, k-1, 1);
                }

                ii res = seg2.get(0,n-1);
                int j = res.se;

                if(seg2.get(u,u).fi == 0)
                    j = u, re[_] = nRes;
                
                if(j == v)
                    nRes = 0;

                val[j] = i;
                seg2.add(j,j,INF);
                seg2.addCircle((j+1)%n, k-1, -1);
                seg1.addCircle((j-k+n+1)%n, k-1, -1);
            }
        }
        if(re[0] && re[1]) return 0;
	    return val[x] > val[y] ? 1 : -1;
    }
	return val[x] > val[y] ? 1 : -1;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 14
• Subtask 3: 0 / 13
• Subtask 4: 17 / 17
• Subtask 5: 0 / 11
• Subtask 6: 0 / 15
• Subtask 7: 0 / 25