제출 #428244

#제출 시각아이디문제언어결과실행 시간메모리
428244Blistering_BarnaclesArranging Shoes (IOI19_shoes)C++14
10 / 100
605 ms761388 KiB
#include "shoes.h" //apig's property //Happiness can be found, even in the darkest of times, if one only remembers to turn on the light //El Pueblo Unido Jamas Sera Vencido //The saddest thing about betrayal? is that it never comes from your enemies //Do or do not... there is no try //Billions of bilious blue blistering barnacles in a thundering typhoon! #include<bits/stdc++.h> #define fast ios_base::sync_with_stdio(0) , cin.tie(0) , cout.tie(0) #define F first #define S second #define pb push_back #define vll vector< ll > #define vi vector< int > #define pll pair< ll , ll > #define pi pair< int , int > #define all(s) s.begin() , s.end() #define sz(s) s.size() #define str string #define md ((s + e) / 2) #define mid ((l + r) / 2) #define msdp(dp) memset(dp , -1 , sizeof dp) #define mscl(dp) memset(dp , 0 , sizeof dp) #define C continue #define R return #define B break #define lx node * 2 #define rx node * 2 + 1 #define br(o) o ; break #define co(o) o ; continue using namespace std; typedef long long ll; ll q, dp[105][100005], a[555555] , b[555555], k, l, m, n, o, p; map < ll , ll > mp; vll adj[555555]; const ll mod = 1e9+7; str s; ll tree[555555] , lazy[555555] ; void lz(ll s , ll e , ll node){ if(lazy[node]){ tree[node] += lazy[node] ; if(s != e){ lazy[lx] += lazy[node] ; lazy[rx] += lazy[node] ; } lazy[node] = 0 ; } } void update(ll s , ll e , ll node , ll l , ll r , ll val){ lz(s , e , node) ; if(s > r || e < l || l > r)R ; if(l <= s && e <= r){ lazy[node] += val ; lz(s , e , node) ; R ; } update(s , md , lx , l , r , val) ; update(md + 1 , e , rx , l , r , val) ; tree[node] = tree[lx] + tree[rx] ; } ll query(ll s , ll e , ll node , ll id){ lz(s , e , node) ; if(s > id || e < id)R 0 ; if(s == id && id == e)R tree[node] ; R query(s , md , lx , id) + query(md + 1 , e , rx , id) ; } queue < ll > low[555555] , high[555555] ; long long count_swaps(std::vector<int> s) { n = sz(s) ; for(ll i = 1 ; i <= n ; i++){ a[i] = s[i - 1] ; if(a[i] < 0)low[abs(a[i])].push(i) ; else high[a[i]].push(i) ; } for(ll i = 1 ; i <= n ; i++){ if(mp[i] || low[abs(a[i])].empty() || high[abs(a[i])].empty())C ; o = low[abs(a[i])].front() , p = high[abs(a[i])].front() ; if(o > p)swap(o , p) ; k += query(1 , n , 1 , p) + p - query(1 , n , 1 , o) - o - 1 + (a[i] > 0) ; update(1 , n , 1 , o + 1 , p , 1) ; mp[o]++ , mp[p]++ ; } R k ; }
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