Submission #428032

#	Time	Username	Problem	Language	Result	Execution time	Memory
428032		Blistering_Barnacles	Arranging Shoes (IOI19_shoes)	C++14	10 / 100	8 ms	13352 KiB

shoes

#include "shoes.h"
//apig's property
//Happiness can be found, even in the darkest of times, if one only remembers to turn on the light
//El Pueblo Unido Jamas Sera Vencido
//The saddest thing about betrayal? is that it never comes from your enemies
//Do or do not... there is no try
//Billions of bilious blue blistering barnacles in a thundering typhoon!
#include<bits/stdc++.h>
#define fast ios_base::sync_with_stdio(0) , cin.tie(0) , cout.tie(0)
#define F first
#define S second
#define pb push_back
#define vll vector< ll >
#define vi vector< int >
#define pll pair< ll , ll >
#define pi pair< int , int >
#define all(s) s.begin() , s.end()
#define sz(s) s.size()
#define str string
#define md ((s + e) / 2)
#define mid ((l + r) / 2)
#define msdp(dp) memset(dp , -1 , sizeof dp)
#define mscl(dp) memset(dp , 0 , sizeof dp)
#define C continue
#define R return
#define B break
#define lx node * 2
#define rx node * 2 + 1
#define br(o) o ; break
#define co(o) o ; continue
using namespace std;
typedef long long ll;
ll q, dp[105][100005], a[555555] , b[555555], k, l, m, n, o, p;
map < ll , ll > mp;
vll adj[555555];
const ll mod = 1e9+7;
str s;
long long count_swaps(std::vector<int> s) {
	n = sz(s) ;
	for(ll i = 1 ; i <= n ; i++){
        a[i] = s[i - 1] ;
	}
	ll cnt = 1 ;
	n *= 2 ;
	k = 0 ;
	while(cnt <= n){
        ll id = 0 ;
        for(ll i = cnt ; i <= n ; i++){
            if(a[i] < 0){
                id = i ;
                B ;
            }
        }
        for(ll i = id ; i > cnt ; i--){
            swap(a[i] , a[i - 1]) ;
            k++ ;
        }
        cnt++ ;
        for(ll i = cnt ; i <= n ; i++){
            if(a[i] == -a[cnt]){
                id = i ;
                B ;
            }
        }
        for(ll i = id ; i > cnt ; i--){
            swap(a[i] , a[i - 1]) ;
            k++ ;
        }
        cnt++ ;
	}
	R k ; 
}

• Subtask 1: 10 / 10
• Subtask 2: 0 / 20
• Subtask 3: 0 / 20
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 15