Submission #427761

#	Time	Username	Problem	Language	Result	Execution time	Memory
427761		Pbezz	Split the Attractions (IOI19_split)	C++14	0 / 100	638 ms	1048580 KiB

split

#include "split.h"
#include <bits/stdc++.h>

using namespace std;

#define ll long long
#define pb push_back
typedef pair<ll,ll> pii;

const ll MAXN = 1e5+5;
const ll INF = 1e9+7;

vector<vector<ll>>adj(MAXN);
int sub[MAXN],cur=1,k,N,chosen=-1,parent;
bool visited[MAXN],fine=true;

	vector<int> des(MAXN);

void dfs(ll node, ll p){//cur esta a contar com este
visited[node]=true;
sub[node]=1; if(!fine)return;

bool ok=true;
for(auto u:adj[node]){if(!fine)return;
if(u==p)continue;

dfs(u,node);
sub[node]+=sub[u];
if(sub[u]>=k)ok=false;
}

if(sub[node]>=k&&ok){
	chosen=node;
	parent=p;
	if(N-sub[node]<k){
	fine=false;
	chosen=-1;
	}

}

}
int mark,lim,cont;
void dfs1(ll node, ll p){//cout<<node<<" "<<p<<endl;
des[node]=mark; cont++;
for(auto u:adj[node]){
if(u==p)continue;
//cout<<u<<" "<<node<<" "<<cont<<" "<<lim<<endl;
if(cont+1<=lim){
dfs1(u,node);
}
}

}

vector<int> find_split(int n,int a,int b,int c,vector<int>p,vector<int> q) {

	int i,m=p.size(); k=min(min(a,b),c); N=n;
	vector<int> res(n);
	int meh[3]={a,b,c}; sort(meh,meh+3);

	for(i=0;i<m;i++){
	adj[p[i]].pb(q[i]);
	adj[q[i]].pb(p[i]);
	}
	for(i=0;i<n;i++)res[i]=0;
	dfs(0,-1);

	if(chosen==-1)return res;

	if(sub[chosen]<n-sub[chosen]){
mark=1; cont=0; lim=meh[0];
	dfs1(chosen,parent);

mark=2; cont=0; lim=meh[1];cout<<endl;
	dfs1(parent,chosen);
	}else{
mark=1; cont=0; lim=meh[0];
	dfs1(parent,chosen);

mark=2; cont=0; lim=meh[1];
	dfs1(chosen,parent);
	}
	for(i=0;i<n;i++){
	res[i]=des[i];
	}

	if(a<=b&&b<=c){

	for(i=0;i<n;i++){

	if(res[i]==0){
	res[i]=2;
	}

	}

	}else if(a<=c&&c<=b){
	for(i=0;i<n;i++){
	if(res[i]==0){
	res[i]=2;
	}else if(res[i]==2){
	res[i]=3;
	}
	}

	}else if(b<=a&&a<=c){

	for(i=0;i<n;i++){
	if(res[i]==0){
	res[i]=3;
	}else if(res[i]==1){
	res[i]=2;
	}else{
	res[i]=1;
	}
	}

	}else if(b<=c&&c<=a){

	for(i=0;i<n;i++){
	if(res[i]==0){
	res[i]=1;
	}else if(res[i]==1){
	res[i]=2;
	}else{
	res[i]=3;
	}
	}

	}else if(c<=b&&b<=a){

	for(i=0;i<n;i++){
	if(res[i]==0){
	res[i]=1;
	}else if(res[i]==1){
	res[i]=3;
	}else{
	res[i]=3;
	}
	}

	}else{//c<=a<=b

	for(i=0;i<n;i++){
	if(res[i]==0){
	res[i]=2;
	}else if(res[i]==1){
	res[i]=3;
	}else{
	res[i]=1;
	}
	}

}




	return res;
}

• Subtask 1: 0 / 7
• Subtask 2: 0 / 11
• Subtask 3: 0 / 22
• Subtask 4: 0 / 24
• Subtask 5: 0 / 36