Submission #427404

#	Time	Username	Problem	Language	Result	Execution time	Memory
427404		lyc	City (JOI17_city)	C++14	8 / 100	259 ms	21712 KiB

Encoder

#include "Encoder.h"

#include <bits/stdc++.h>
using namespace std;

#define TRACE(x) cerr << #x << " :: " << x << endl
#define _ << " " <<
#define SZ(x) ((int)(x).size())
#define ALL(x) (x).begin(),(x).end()
#define FOR(i,a,b) for(int i=(a);i<=(b);++i)
#define RFOR(i,a,b) for(int i=(a);i>=(b);--i)
typedef long long ll;
typedef pair<int,int> ii;

const int mxN = 250001;

int N;
vector<int> al[mxN];

int bits[mxN], code[mxN];

void dfs(int u, int p) {
    int nc = 0;
    for (int& v : al[u]) if (v != p) {
        ++nc;
    }

    if (nc > 0) {
        --nc;
        int shift = 0;
        while (nc) shift++, nc >>= 1;
        shift = max(shift,1);
        int i = 0;
        for (int& v : al[u]) if (v != p) {
            bits[v] = bits[u] + shift;
            code[v] = (code[u]<<shift) | i;
            //TRACE(u _ v _ i _ code[v] _ bits[v]);
            dfs(v,u);
            ++i;
        }
    }

    //TRACE(u _ nc _ bits[u] _ code[u]);
}

void Encode(int N, int A[], int B[])
{
    FOR(i,0,N-2){
        al[A[i]].push_back(B[i]);
        al[B[i]].push_back(A[i]);
    }

    bits[0] = 0, code[0] = 0;
    dfs(0,-1);

	for (int i = 0; i < N; ++i) {
		Code(i, (ll)bits[i] | ((ll)code[i]<<5));
	}
}

Device

#include "Device.h"

#include <bits/stdc++.h>
using namespace std;

#define TRACE(x) cerr << #x << " :: " << x << endl
#define _ << " " <<
#define SZ(x) ((int)(x).size())
#define ALL(x) (x).begin(),(x).end()
#define FOR(i,a,b) for(int i=(a);i<=(b);++i)
#define RFOR(i,a,b) for(int i=(a);i>=(b);--i)
typedef long long ll;
typedef pair<int,int> ii;

const int MN = 1e6+5;
const int mod = 1e9+7;

void InitDevice()
{

}

int Answer(long long S, long long T)
{

    int b1 = S&((1<<5)-1), b2 = T&((1<<5)-1);

    if (b1 == b2) return 2;
    if (b1 == 0) return 1;
    if (b2 == 0) return 0;

    S >>= 5;
    T >>= 5;
    if (b1 < b2) {
        if (S == (T>>(b2-b1))) return 1;
        return 2;
    } else {
        if ((S>>(b1-b2)) == T) return 0;
        return 2;
    }

	return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 0 / 92