#include "shoes.h"
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
//n = 1 its either 1 or 0
//n = 8 we can brutazo
//all shoes are same, we just need to get all inversion (even is left, odd is right)
//all shoes need to travel n?
//eta ~ 25 minutes
/*full solutions*/
//O(N^2)
/*
dp[n][i]
//min swaps at position i after considering n pairs?
*/
/*SUBTASK 1, 3, 4*/
/*
long long count_swaps(vector<int> s) {
ll ans = 0;
int n = s.size();
int first = 0;
for(int i =0; i<n; i++){
if(s[i] < 0){
ans += abs(i - first);
first +=2;
}
}
return ans;
}
*/
/*SUBTASK 2*/
//something is wrong, ill come back to it later
//i need to think more
long long count_swaps(vector<int> s) {
ll ans = 1e18;
int n = s.size();
vector<int> lefts(n/2);
int cntleft = 0;
for(int i =0; i<n; i++){
if(s[i] < 0){
lefts[cntleft++] = i;
}
}
do{
ll posans = 0;
vector<bool> available(n, 1);
//for(int i =0; i<n/ 2; i++) cout << lefts[i]<<", "; cout <<endl;
for(int l =0; l<n/2; l++){
//get first availabe
int firstright =-1;
for(int i =0; i<n ;i++){
if(available[i] and s[i] == -s[lefts[l]]){
firstright = i;
available[i] = false;
break;
}
}
ll dist1 = abs(lefts[l] - 2 * l);
if(lefts[l]< 2* (l)){
//cout <<"a\n";
dist1 -= 2 * (l)-1 ;
}
ll dist2 = abs(firstright -( 2 * l + 1));
if(firstright< 2* (l)+1){
//cout <<"b\n";
dist2 -= 2 * (l);
}
//cout << lefts[l]<<", "<<firstright<<": "<<dist1<<", "<<dist2<<endl;
posans += dist1 + dist2;
}
ans = min(ans, posans);
//cout << posans<<endl<<endl;
}while(next_permutation(lefts.begin(), lefts.end()));
return ans;
}
/***********/
