이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "wiring.h"
#include <bits/stdc++.h>
using namespace std;
#define LL long long
const LL INF = 1e9;
const LL LINF = 1e18;
const int N = 2e3+10;
LL dp[N][N][2][2];
int n,m;
vector<int>R,B;
LL solve(int i,int j,int t1,int t2){
if(i==n-1&&j==m-1&&t1&&t2)
return 0;
if(dp[i][j][t1][t2]!=-1)
return dp[i][j][t1][t2];
dp[i][j][t1][t2] = LINF;
if(t1&&i<n-1)
dp[i][j][t1][t2] = min(dp[i][j][t1][t2],solve(i+1,j,0,t2));
if(t2&&j<m-1)
dp[i][j][t1][t2] = min(dp[i][j][t1][t2],solve(i,j+1,t1,0));
dp[i][j][t1][t2] = min(dp[i][j][t1][t2],solve(i,j,1,1)+abs(R[i]-B[j]));
return dp[i][j][t1][t2];
}
long long min_total_length(std::vector<int> r, std::vector<int> b) {
n = r.size(),m = b.size();
LL sum1 = 0,sum2 = 0;
for(auto x:r)
sum1 += 0ll+x;
for(auto x:b)
sum2 += 0ll+x;
LL ret = 1ll*sum2-r.back()*m + 1ll*b.front()*n-sum1;
ret -= b[0]-r[n-1];
if(n>1&&m>1)
ret -= (b[0]-r[n-1]);
return ret;
}
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