Submission #425285

#	Time	Username	Problem	Language	Result	Execution time	Memory
425285		songc	Vim (BOI13_vim)	C++14	42.50 / 100	37 ms	34108 KiB

vim

#include <bits/stdc++.h>
#define pb push_back
#define fi first
#define se second
#define Mup(a,x) a=max(a, x)
#define mup(a,x) a=min(a, x)
#define all(v) v.begin(),v.end()
#define lb lower_bound
#define INF (1ll<<60)
#define MOD 1'000'000'007 
using namespace std;
typedef long long LL;
typedef pair<int,int> pii;

int M, N, X, sum, ans=MOD;
int A[70707], D[70707][11][11];
bool E[70707];

int main(){
	char c;
	bool tf = false;
	scanf("%d", &M);
	for (int i=0; i<M; i++){
		scanf(" %c", &c);
		if (c != 'e'){
			A[++N] = c-'a'+1+(c<'e'?1:0);
			if (tf) X = N;
			E[N] = tf, tf = false;
		}
		else tf = true, sum += 2;
	}
	if (!X){puts("0"); return 0;}
	memset(D, 1, sizeof D);
	for (int i=2; i<=10; i++) D[1][i][0] = 2;
	for (int i=1; i<N; i++){
		for (int j=2; j<=10; j++){
			if (A[i+1] == j){
				if (i+1>=X) ans = min(ans, min(D[i][j][0], D[i][j][1]));
				for (int k=2; k<=10; k++) D[i+1][k][0] = min(D[i+1][k][0], D[i][j][0]+2);
			}
			else{
				if (!E[i+1]) D[i+1][j][0] = min(D[i+1][j][0], D[i][j][0]);
				D[i+1][j][1] = min(D[i+1][j][1], min(D[i][j][0], D[i][j][1])+1);
				for (int k=2; k<=10; k++) D[i+1][j][k] = min(D[i+1][j][k], D[i][j][0]+3);
			}
			for (int k=2; k<=10; k++){
				if (A[i+1] == j){
					if (j == k) for (int l=2; l<=10; l++) D[i+1][l][0] = min(D[i+1][l][0], D[i][j][k]+2);
					else D[i+1][k][0] = min(D[i+1][k][0], D[i][j][k]);
				}
				else if (A[i+1] != k) D[i+1][j][k] = min(D[i+1][j][k], D[i][j][k]+1);
			}
		}
	}
	printf("%d\n", ans+sum);
	return 0;
}

Compilation message (stderr)

vim.cpp: In function 'int main()':
vim.cpp:22:7: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   22 |  scanf("%d", &M);
      |  ~~~~~^~~~~~~~~~
vim.cpp:24:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   24 |   scanf(" %c", &c);
      |   ~~~~~^~~~~~~~~~~

• Subtask 1: 37.5 / 50
• Subtask 2: 5 / 10
• Subtask 3: 0 / 40