# |
Submission time |
Handle |
Problem |
Language |
Result |
Execution time |
Memory |
42502 |
2018-02-28T02:22:52 Z |
funcsr |
Robots (APIO13_robots) |
C++14 |
|
121 ms |
59236 KB |
#include <iostream>
#include <vector>
using namespace std;
typedef pair<int, int> P;
#define rep(i, n) for (int i=0; i<(n); i++)
#define pb push_back
#define all(x) x.begin(), x.end()
#define uniq(x) x.erase(unique(all(x)), x.end())
#define INF 1000001919
#define _1 first
#define _2 second
const int DX[4] = {-1, 0, 1, 0};
const int DY[4] = {0, -1, 0, 1};
int N, W, H;
char A[500][500];
P dst[500][500][4];
P f(int x, int y, int d) {
if (dst[x][y][d] != P(-2, -2)) return dst[x][y][d];
dst[x][y][d] = P(-1, -1);
int nx = x+DX[d], ny = y+DY[d], nd = d;
if (nx<0||nx>=W||ny<0||ny>=H||A[nx][ny]=='#') return dst[x][y][d] = P(x, y);
if (A[nx][ny] == 'A') nd = (d+3)%4;
if (A[nx][ny] == 'C') nd = (d+1)%4;
return dst[x][y][d] = f(nx, ny, nd);
}
const int MAX_D = 10*500*500;
int X[9], Y[9];
int dp[9][9][500][500];
vector<P> Q[MAX_D];
bool used[500][500];
void bfs(int D[500][500]) {
rep(i, W) rep(j, H) used[i][j] = false;
rep(i, MAX_D) Q[i].clear();
rep(x, W) rep(y, H) if (D[x][y] != INF) Q[D[x][y]].pb(P(x, y));
vector<P> q;
rep(r, MAX_D) {
vector<P> nq;
for (P p : Q[r]) {
int x = p._1, y = p._2;
if (!used[x][y]) {
used[x][y] = true;
q.pb(P(x, y));
}
}
for (P p : q) {
int x = p._1, y = p._2;
rep(k, 4) {
P np = dst[x][y][k];
if (np._1 != -1 && !used[np._1][np._2]) {
used[np._1][np._2] = true;
D[np._1][np._2] = r+1;
nq.pb(np);
}
}
}
q.clear();
swap(q, nq);
}
}
int main() {
cin >> N >> W >> H;
rep(y, H) rep(x, W) {
cin >> A[x][y];
if ('0' <= A[x][y] && A[x][y] <= '9') X[A[x][y]-'1'] = x, Y[A[x][y]-'1'] = y;
}
rep(x, W) rep(y, H) rep(d, 4) dst[x][y][d] = P(-2, -2);
rep(x, W) rep(y, H) if (A[x][y] != '#') rep(d, 4) f(x, y, d);
rep(i, N) rep(j, N) rep(x, W) rep(y, H) dp[i][j][x][y] = INF;
rep(i, N) dp[i][i][X[i]][Y[i]] = 0;
for (int len=1; len<=N; len++) {
rep(l, N) {
int r = l+len-1;
if (r >= N) break;
rep(x, W) rep(y, H) for (int k=l; k<r; k++) {
dp[l][r][x][y] = min(dp[l][r][x][y], dp[l][k][x][y]+dp[k+1][r][x][y]);
}
bfs(dp[l][r]);
}
}
int m = INF;
rep(x, W) rep(y, H) m = min(m, dp[0][N-1][x][y]);
cout << m << "\n";
return 0;
}
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
120 ms |
59000 KB |
Output is correct |
2 |
Incorrect |
121 ms |
59236 KB |
Output isn't correct |
3 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
120 ms |
59000 KB |
Output is correct |
2 |
Incorrect |
121 ms |
59236 KB |
Output isn't correct |
3 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
120 ms |
59000 KB |
Output is correct |
2 |
Incorrect |
121 ms |
59236 KB |
Output isn't correct |
3 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
120 ms |
59000 KB |
Output is correct |
2 |
Incorrect |
121 ms |
59236 KB |
Output isn't correct |
3 |
Halted |
0 ms |
0 KB |
- |