제출 #424726

#제출 시각아이디문제언어결과실행 시간메모리
424726alishahali1382Arranging Shoes (IOI19_shoes)C++14
10 / 100
4 ms4996 KiB
#include "shoes.h" #include<bits/stdc++.h> #pragma GCC optimize("O2") using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define debug(x) {cerr<<#x<<"="<<x<<"\n";} #define debug2(x, y) {cerr<<"{"<<#x<<", "<<#y<<"}={"<<x<<", "<<y<<"}\n";} #define debugp(p) {cerr<<#p<<"={"<<p.first<<", "<<p.second<<"}\n";} #define debugv(abcd) {cerr<<#abcd<<": ";for (auto dcba:abcd) cerr<<dcba<<", ";cerr<<"\n";} #define pb push_back #define SZ(x) ((int)x.size()) #define all(x) x.begin(), x.end() const int inf=1000001000; // 1e9 const ll INF=10000000010000000; // 1e16 const int mod=1000000007; const int MAXN=200010, LOG=19; ll ans; // :( int n, m, k; int A[MAXN]; vector<int> vec[MAXN]; ll count_swaps(vector<int> S){ n=SZ(S); for (int i=0; i<n; i++){ int x=S[i], y=1; if (x<0) x=-x, y=-1; if (vec[x].size() && S[vec[x].back()]*y<0){ A[i]=A[vec[x].back()]=m++; vec[x].pop_back(); } else vec[x].pb(i); } for (int i=0; i<n; i++) A[i]=2*A[i]+(S[i]>0); for (int i=0; i<n; i++) for (int j=0; j<i; j++) ans+=(A[j]>A[i]); return ans; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...