제출 #423529

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
423529		patrikpavic2	Financial Report (JOI21_financial)	C++17	100 / 100	709 ms	37972 KiB

Main

#include <cstdio>
#include <cstring>
#include <vector>
#include <algorithm>
#include <set>

#define PB push_back

using namespace std;

const int N = 3e5 + 500;
const int OFF = (1 << 19);
const int INF = 0x3f3f3f3f;

int n, d, A[N], sm[N];
vector < int > saz, rv[N];
set < int > S;
int T[2 * OFF], dp[N], sol;

void update(int i, int x){
	T[OFF + i] = max(T[OFF + i], x);
	for(i = (i + OFF) / 2 ; i ; i /= 2)
		T[i] = max(T[2 * i], T[2 * i + 1]);
}

int query(int i, int a, int b, int lo, int hi){
	if(lo <= a && b <= hi) return T[i];
	if(a > hi || b < lo) return 0;
	return max(query(2 * i, a, (a + b) / 2, lo, hi), query(2 * i + 1, (a + b) / 2 + 1, b, lo, hi));
}

inline void remove(int l, int r){
	for(auto it = S.lower_bound(l);it != S.end() && *it <= r;it = S.erase(it));
}


int main(){
	scanf("%d%d", &n, &d);
	for(int i = 0;i < n;i++){
		scanf("%d", A + i);
		saz.PB(A[i]); S.insert(i);
	}
	sort(saz.begin(), saz.end());
	saz.erase(unique(saz.begin(), saz.end()), saz.end());
	for(int i = 0;i < n;i++){
		A[i] = lower_bound(saz.begin(), saz.end(), A[i]) - saz.begin();
		rv[A[i]].PB(i);
	}
	for(int i = 0;i < n;i++){
		for(int j : rv[i])
			remove(j - d + 1, j);
		for(int j : rv[i]){
			sm[j] = ((int)S.size() == 0 || *S.begin() > j ? 0 : *(--S.lower_bound(j)));
		}
	}
	for(int i = 0;i < n;i++){
		reverse(rv[i].begin(), rv[i].end());
		for(int j : rv[i]){
			dp[j] = query(1, 0, OFF - 1, sm[j], j) + 1;
			update(j, dp[j]); sol = max(sol, dp[j]);
		}
	}
	printf("%d\n", sol);
	return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'int main()':
Main.cpp:38:7: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   38 |  scanf("%d%d", &n, &d);
      |  ~~~~~^~~~~~~~~~~~~~~~
Main.cpp:40:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   40 |   scanf("%d", A + i);
      |   ~~~~~^~~~~~~~~~~~~

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 20 / 20
• Subtask 4: 12 / 12
• Subtask 5: 5 / 5
• Subtask 6: 35 / 35