Submission #421719

#	Time	Username	Problem	Language	Result	Execution time	Memory
421719		Keshi	Seats (IOI18_seats)	C++17	0 / 100	4080 ms	56628 KiB

seats

//In the name of God
#include <bits/stdc++.h>
#include "seats.h"
#pragma GCC optimize("O2")
#pragma GCC optimize("Ofast")
using namespace std;

typedef int ll;
typedef pair<ll, ll> pll;

const ll maxn = 1e6 + 100;
const ll mod = 1e9 + 7;
const ll inf = 1e9;

#define fast_io ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define pb push_back
#define Mp make_pair
#define F first
#define S second
#define Sz(x) ll((x).size())
#define all(x) (x).begin(), (x).end()
#define lc (id << 1)
#define rc (lc | 1)


struct rect{
	ll mnx, mny, mxx, mxy;
};

ll h, w;
pll p[maxn];
rect seg[maxn << 2];

rect mrg(rect l, rect r){
	rect m = {min(l.mnx, r.mnx), min(l.mny, r.mny), max(l.mxx, r.mxx), max(l.mxy, r.mxy)};
	return m;
}

void bld(ll id, ll s, ll e){
	if(e - s == 1){
		seg[id] = {p[s].F, p[s].S, p[s].F, p[s].S};
		return;
	}
	ll mid = (s + e) >> 1;
	bld(lc, s, mid);
	bld(rc, mid, e);
	seg[id] = mrg(seg[lc], seg[rc]);
	return;
}
void upd(ll id, ll s, ll e, ll x){
	if(x < s || e <= x) return;
	if(e - s == 1){
		seg[id] = {p[s].F, p[s].F, p[s].S, p[s].S};
		return;
	}
	ll mid = (s + e) >> 1;
	bld(lc, s, mid);
	bld(rc, mid, e);
	seg[id] = mrg(seg[lc], seg[rc]);
	return;
}
rect get(ll id, ll s, ll e, ll x){
	if(x >= e) return seg[id];
	ll mid = (s + e) >> 1;
	if(x <= mid) return get(lc, s, mid, x);
	return mrg(get(lc, s, mid, x), get(rc, mid, e, x));
}
rect get(ll x){
	return get(1, 0, h * w, x);
}

void give_initial_chart(int H, int W, vector<int> R, vector<int> C){
	h = H;
	w = W;
	for(ll i = 0; i < H * W; i++){
		p[i] = Mp(R[i], C[i]);
	}
	bld(1, 0, H * W);
	return;
}

inline ll cal(rect rct){
	return (rct.mxx - rct.mnx + 1) * (rct.mxy - rct.mny + 1);
}

ll solve(){
	ll x = 1;
	ll ans = 1;
	while(x != h * w){
		ll y = cal(get(x));
		if(y == x){
			ans++;
			x++;
		}
		else x = y;
	}
	return ans;
}

int swap_seats(int a, int b){
	swap(p[a], p[b]);
	upd(1, 0, h * w, a);
	upd(1, 0, h * w, b);
	return 1;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 6
• Subtask 3: 0 / 20
• Subtask 4: 0 / 6
• Subtask 5: 0 / 33
• Subtask 6: 0 / 30