# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
42014 | OneSubmissionMan | 수열 (APIO14_sequence) | C++11 | 85 ms | 6908 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
# include <bits/stdc++.h>
# define F first
# define S second
# define mp make_pair
// everything go according to my plan
# define pb push_back
# define sz(a) (int)(a.size())
# define vec vector
// shimkenttin kyzdary, dzyn, dzyn, dzyn...
# define y1 Y_U_NO_y1
# define left Y_U_NO_left
# define right Y_U_NO_right
using namespace std;
typedef pair <int, int> pii;
typedef long long ll;
typedef long double ld;
const int Mod = (int)1e9 + 7;
const int MX = 1073741822;
const ll MXLL = 4e18;
const int Sz = 1110111;
// a pinch of soul
inline void Read_rap () {
ios_base :: sync_with_stdio(0);
cin.tie(0); cout.tie(0);
}
inline void randomizer3000 () {
unsigned int seed;
asm ("rdtsc" : "=A"(seed));
srand (seed);
}
void files (string problem) {
if (fopen ((problem + ".in").c_str(),"r")) {
freopen ((problem + ".in").c_str(),"r",stdin);
freopen ((problem + ".out").c_str(),"w",stdout);
}
}
void localInput (string in = "s") {
if (fopen (in.c_str(), "r"))
freopen (in.c_str(), "r", stdin);
else {
cerr << "Input file not found" << endl;
}
}
const int K = 200 + 1;
const int N = 1e5 + 1;
int n;
int k;
ll pref[Sz];
int a[Sz];
int pr[K][N];
struct CHT {
struct line {
ll k, b;
ll get (ll x) {
return k * x + b;
}
};
vec<line> r;
vec<int> id;
int ptr;
CHT() : ptr(0) {}
void clear() {
r.clear();
id.clear();
ptr = 0;
}
ld intersection (line &a, line &b) {
return ((ld)b.b - a.b) / (a.k - b.k);
}
void add_line (line last, int Id) {
while (sz(r) >= 2 && intersection (r[sz(r) - 2], r[sz(r)-1]) > intersection (r[sz(r)-2], last)) {
r.pop_back();
id.pop_back();
}
r.pb (last);
id.pb (Id);
}
pair <ll, int> get (ll x) {
ptr = min (ptr, sz(r) - 1);
while (ptr + 1 < sz(r) && intersection (r[ptr], r[ptr + 1]) < x)
ptr++;
return {r[ptr].get (x), id[ptr]};
}
};
int main()
{
Read_rap();
//localInput();
cin >> n >> k;
for (int i = 1; i <= n; i++)
cin >> a[i];
for (int i = 1; i <= n; i++)
pref[i] = pref[i - 1] + a[i];
ll dp[n + 1] = {0}, nw[n + 1] = {0};
CHT T;
for (int i = 1; i <= k; i++) {
T.clear();
for (int j = i + 1; j <= n; j++) {
j--;
T.add_line ( {pref[j], -pref[j] * pref[j] + dp[j]}, j);
j++;
tie (nw[j], pr[i][j]) = T.get (pref[j]);
}
for (int j = 1; j <= n; j++)
dp[j] = nw[j];
/*
for (int j = 1; j <= n; j++)
cout << dp[j] << ' ';
cout << endl;
*/
}
cout << dp[n] << endl;
for (int i = k, j = n; i >= 1; ) {
j = pr[i][j];
i--;
assert (j);
cout << j << ' ';
}
return 0;
}
// Coded by Z..
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