제출 #419886

#제출 시각아이디문제언어결과실행 시간메모리
419886BertedFinancial Report (JOI21_financial)C++14
100 / 100
583 ms11440 KiB
#include <iostream> #include <algorithm> #include <set> #define pii pair<int, int> #define fst first #define snd second using namespace std; const int SZ = (1 << 20) + 5; int N, D; int DP[300001], seg[SZ]; pii A[300001]; set<pii> S; void upd(int idx, int L, int R, int x, int v) { if (L == R) {seg[idx] = v;} else if (L < R) { int M = L + R >> 1; if (x <= M) upd(2 * idx, L, M, x, v); else upd(2 * idx + 1, M + 1, R, x, v); seg[idx] = max(seg[2 * idx], seg[2 * idx + 1]); } } int qry(int idx, int L, int R, int l, int r) { l = max(L, l); r = min(R, r); if (l <= r) { if (L == l && R == r) return seg[idx]; else { int M = L + R >> 1; return max(qry(2 * idx, L, M, l, r), qry(2 * idx + 1, M + 1, R, l, r)); } } return 0; } void delet(int x) { auto it = S.lower_bound({x + 1, -1}); if (it != S.begin()) { it = prev(it); if (it -> fst <= x && x <= it -> snd) { pii r = *it; S.erase(it); if (x - r.fst >= D) S.insert({r.fst, x - 1}); if (r.snd - x >= D) S.insert({x + 1, r.snd}); } } } int main() { ios :: sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> N >> D; for (int i = 0; i < N; i++) { cin >> A[i].fst; A[i].snd = -(i + 1); } sort(A, A + N); int res = 0; S.insert({1, N}); for (int i = 0; i < N; i++) { //cerr << "i: " << i << "\n"; int id = -A[i].snd; delet(id); //cerr << "id: " << id << "\n"; int l; auto it = S.upper_bound({id, -1}); if (it != S.begin()) {l = prev(it) -> snd + 1;} else {l = 1;} //cerr << "l: " << l << "\n"; DP[id] = qry(1, 1, N, l, id) + 1; upd(1, 1, N, id, DP[id]); res = max(res, DP[id]); } cout << res << "\n"; return 0; }

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'void upd(int, int, int, int, int)':
Main.cpp:23:13: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
   23 |   int M = L + R >> 1;
      |           ~~^~~
Main.cpp: In function 'int qry(int, int, int, int, int)':
Main.cpp:38:14: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
   38 |    int M = L + R >> 1;
      |            ~~^~~
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