이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//Arayi
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <string>
#include <queue>
#include <stack>
#include <algorithm>
#include <math.h>
#include <vector>
#include <cstring>
#include <ctime>
#include <set>
#include <bitset>
#include <map>
#include <unordered_map>
#include <unordered_set>
#include <iomanip>
#include <ctime>
#include <climits>
#include <cassert>
#include <chrono>
#include <random>
#include <complex>
#define fr first
#define sc second
#define MP make_pair
#define ad push_back
#define PB push_back
#define fastio ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define lli long long int
#define y1 arayikhalatyan
#define j1 jigglypuff
#define ld long double
#define itn int
#define pir pair<int, int>
#define all(x) (x).begin(), (x).end()
#define str string
#define enl endl
#define en endl
#define cd complex<long double>
#define vcd vector<cd>
#define vii vector<int>
#define vlli vector<lli>
using namespace std;
lli gcd(lli a, lli b) { return (b == 0LL ? a : gcd(b, a % b)); }
ld dist(ld x, ld y1, ld x2, ld y2)
{
return sqrt((x - x2) * (x - x2) + (y1 - y2) * (y1 - y2));
}
lli S(lli a)
{
return (a * (a + 1LL)) / 2;
}
mt19937 rnd(363542);
char vow[] = { 'a', 'e', 'i', 'o', 'u' };
int dx[] = { 0, -1, 0, 1, -1, -1, 1, 1, 0 };
int dy[] = { -1, 0, 1, 0, -1, 1, -1, 1, 0 };
const int N = 1e6 + 30;
const lli mod = 1e9 - 1;
const ld pi = acos(-1);
const int T = 550;
lli bp(lli a, lli b = mod - 2LL)
{
lli ret = 1;
while (b)
{
if (b & 1) ret *= a, ret %= mod;
a *= a;
a %= mod;
b >>= 1;
}
return ret;
}
ostream& operator<<(ostream& c, pir a)
{
c << a.fr << " " << a.sc;
return c;
}
template<class T>
void maxi(T& a, T b)
{
a = max(a, b);
}
template <class T>
void mini(T& a, T b)
{
a = min(a, b);
}
int n, q;
lli s1, t1, a, b;
lli t[4*N], flg[4*N];
void push(int nd)
{
flg[nd * 2] += flg[nd];
flg[nd * 2 + 1] += flg[nd];
t[nd] += flg[nd];
flg[nd] = 0;
}
void upd(int l, int r, int v, int nl = 0, int nr = n , int nd = 1)
{
push(nd);
if(l > nr || r < nl) return;
if(l == nl && r == nr)
{
flg[nd] += v;
push(nd);
return;
}
int mid = (nl + nr)/2;
upd(l, min(mid, r), v, nl, mid, nd * 2);
upd(max(mid + 1, l), r, v, mid + 1, nr, nd * 2 + 1);
t[nd] = t[nd * 2] + t[nd* 2 + 1];
}
lli qry(int q, int l = 0, int r = n, int nd = 1)
{
push(nd);
if(l > q || r < q) return 0;
if(l==r) return t[nd];
int mid = (l + r)/ 2;
return qry(q, l, mid, nd*2) + qry(q, mid + 1, r, nd * 2 + 1);
}
int main()
{
fastio;
cin >> n >> q >> s1 >> t1;
int x;
cin >> x;
upd(0, 0, x);
for (int i = 0; i < n; i++)
{
cin >> x;
upd(i + 1, i + 1, x);
int sm = qry(i);
if(sm >= x) a += sm - x;
else b += x - sm;
}
//cout << a*t1-b*s1 << endl;
while(q--)
{
lli l, r, v;
cin >> l >> r >> v;
lli sm = qry(l - 1), s = qry(l);
if(sm >= s) a -= sm - s;
else b -= s - sm;
upd(l, r, v);
s += v;
if(sm >= s) a += sm - s;
else b += s - sm;
if(r < n)
{
sm = qry(r) - v, s = qry(r + 1);
//cout << sm << " "<< s << endl;
if(sm >= s) a -= sm - s;
else b -= s - sm;
sm += v;
if(sm >= s) a += sm - s;
else b += s - sm;
}
cout << a*t1 - b*s1 << "\n";
}
return 0;
}
/*
5 4 4
1 2
3 1
3 4
5 3
4 5 2 3
2 1 3 1
1 3 5
2 3 4 5
2 1 3 1
__
*(><)*
\/ /
||/
--||
||
/\
/ \
/ \
*/
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