Submission #419236

#TimeUsernameProblemLanguageResultExecution timeMemory
419236usachevd0Making Friends on Joitter is Fun (JOI20_joitter2)C++17
0 / 100
5010 ms340 KiB
#include <bits/stdc++.h> using namespace std; #define fi first #define se second #define mp make_pair #define pb push_back #define all(a) (a).begin(), (a).end() #define Time (clock() * 1.0 / CLOCKS_PER_SEC) using ll = long long; using ull = unsigned long long; using pii = pair<int, int>; using pil = pair<int, ll>; using pli = pair<ll, int>; using pll = pair<ll, ll>; using ld = long double; template<typename T1, typename T2> bool chkmin(T1& x, T2 y) { return y < x ? (x = y, true) : false; } template<typename T1, typename T2> bool chkmax(T1& x, T2 y) { return y > x ? (x = y, true) : false; } void debug_out() { cerr << endl; } template<typename T1, typename... T2> void debug_out(T1 A, T2... B) { cerr << ' ' << A; debug_out(B...); } template<typename T> void mdebug_out(T* a, int n) { for (int i = 0; i < n; ++i) cerr << a[i] << ' '; cerr << endl; } #ifdef LOCAL #define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__) #define mdebug(a, n) cerr << #a << ": ", mdebug_out(a, n) #else #define debug(...) 1337 #define mdebug(a, n) 1337 #endif template<typename T> ostream& operator << (ostream& stream, const vector<T>& v) { for (auto& x : v) stream << x << ' '; return stream; } template<typename T1, typename T2> ostream& operator << (ostream& stream, const pair<T1, T2>& p) { return stream << p.first << ' ' << p.second; } const int maxN = 100; int n, m; bool G[maxN][maxN], H[maxN][maxN]; int32_t main() { #ifdef LOCAL freopen("in", "r", stdin); #endif ios::sync_with_stdio(0); cin.tie(0); cin >> n >> m; for (int i = 0; i < m; ++i) { int a, b; cin >> a >> b; --a; --b; G[a][b] = 1; for (int i = 0; i < n; ++i) for (int j = 0; j < n; ++j) H[i][j] = G[i][j]; int ans = i + 1; while (true) { int added = false; for (int a = 0; a < n && !added; ++a) for (int b = 0; b < n && !added; ++b) if (a != b) for (int c = 0; c < n && !added; ++c) if (c != a && c != b) if (H[a][b] && H[b][c] && H[c][b] && !H[a][c]) { H[a][c] = 1; ++ans; added = true; } if (!added) break; } cout << ans << '\n'; } return 0; }
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