제출 #418585

#제출 시각아이디문제언어결과실행 시간메모리
418585ChaskaHorses (IOI15_horses)C++11
37 / 100
116 ms29892 KiB
#include "horses.h"
#include <bits/stdc++.h>
#define fo(a,b,c) for (int a=b;a<=c;a++)
using namespace std;
const int MAXN = 5e5+5,mod = 1e9+7;
typedef long long ll;
int n,x[MAXN],y[MAXN];
ll st[4*MAXN],r;
void ini(int no,int in,int fin)
{
	if (in == fin) {
		st[no] = x[in];
		return;
	} 
	int mid=(in+fin)/2;
	ini(no*2+1,in,mid);
	ini(no*2+2,mid+1,fin);
	st[no] = st[no*2+1]*st[no*2+2];
	st[no]%= mod;
	return;
}
void get(int no,int in,int fin,int u,int v)
{
	if (fin < u || in > v) return;
	if (u<=in && fin <= v){
		r *= st[no];
		r %= mod;
		return;
	}
	int mid=(in+fin)/2;
	get(no*2+1,in,mid,u,v);
	get(no*2+2,mid+1,fin,u,v);
	return;
}
void upd(int no,int in,int fin,int u,int v)
{
		if (fin < u || in > u) return;
	if (u<=in && fin <= u){
		st[no] = v;
		return;
	}
	int mid=(in+fin)/2;
	upd(no*2+1,in,mid,u,v);
	upd(no*2+2,mid+1,fin,u,v);
	st[no] = st[no*2+1]*st[no*2+2];
	st[no]%= mod;
	return;
}
int sol()
{
	ll k = 0; /// respuesta optima, empezando en pos = -1
	ll res = -1; // indice res optima
	ll q=1; // caballos
	fo(i,max(0,n-35),n-1) {
		q *= x[i];
		if (k<=q) {
			res = i;
			k = y[i];
			q = 1;
		} else {
			q *= y[i];
			if (k<=q) {
				res = i;
				k = y[i];
				q = 1;
			} else {
				q /= y[i];
			}
		}
	}
	r=1;
	get(0,0,n-1,0,res);
	r %= mod;
	r *= y[res];
	r %= mod;
	return r;
}
int init(int N, int X[], int Y[]) {
	n = N;
	
	fo(i,0,n-1) x[i] = X[i];
	fo(i,0,n-1) y[i] = Y[i];
	ini(0,0,n-1);
	return sol();
}

int updateX(int pos, int val) {	
	x[pos] = val;
	upd(0,0,n-1,pos,val);
	return sol();
}

int updateY(int pos, int val) {
	y[pos] = val;
	return sol();
}

컴파일 시 표준 에러 (stderr) 메시지

horses.cpp: In function 'int sol()':
horses.cpp:72:16: warning: conversion from 'll' {aka 'long long int'} to 'int' may change value [-Wconversion]
   72 |  get(0,0,n-1,0,res);
      |                ^~~
horses.cpp:76:9: warning: conversion from 'll' {aka 'long long int'} to 'int' may change value [-Wconversion]
   76 |  return r;
      |         ^
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