# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
418292 | JediMaster11 | Mechanical Doll (IOI18_doll) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define fo(a, b, c) for (int a = b; a < c; a++)
#define ll long long
#define print(x) cout << x << "\n";
ll recur(int l, int r, int *h)
{ // r is non-inclsuive
if (r - l <=1)
{
return h[l];
}
int maxH = -1;
fo(i, l, r)
{
maxH = max(maxH, h[i]);
}
vector<pair<pair<int, int>, ll>> aves;
// stores the left and right, and then the sum of the middle
int leftH = l;
fo(i, l, r)
{
if (h[i] == maxH)
{
ll tmp = recur(leftH, i, h);
aves.push_back({{leftH, i}, tmp});
leftH = i + 1;
}
}
if (leftH != r)
{
ll tmp = recur(leftH, r, h);
aves.push_back({{leftH, r}, tmp});
}
int index=-1;
double minAve = maxH + 1;
fo(i,0,aves.size()){
double maxtmp = 0.0 + aves[i].second / (aves[i].first.second - aves[i].first.first+1);
if(maxtmp < minAve){
minAve=maxtmp;
index=i;
}
}
ll numMax = (r - aves[index].first.second) + (aves[index].first.first-l);
return 1ll * numMax * maxH + aves[index].second;
}
//looking for smallest ave
// h - heights
// l, r - left and right bounds of each meeting
ll minCosts[750000];
ll *minimum_costs(int *h, int *l, int *r)
{
int numMeetings = sizeof(l) / sizeof(l[0]);
// ll minCosts[numMeetings];
fo(i, 0, numMeetings)
{
minCosts[i] = recur(l[i], r[i] + 1, h);
}
return minCosts;
}
// int main()
// {
// ios::sync_with_stdio(0);
// cin.tie(0);
// int h[] = {2, 4, 3, 5};
// int l[] = {0, 1};
// int r[] = {2, 3};
// ll* tm = minimum_costs(h, l, r);
// fo(i,0,sizeof(l)/sizeof(l[0])){
// print(tm[i]);
// }
// }