Submission #417761

#	Time	Username	Problem	Language	Result	Execution time	Memory
417761		MarcoMeijer	Zoltan (COCI16_zoltan)	C++14	140 / 140	437 ms	27212 KiB

zoltan

#include <bits/stdc++.h>
using namespace std;
 
// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e18
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
 
// input
template<class T> void IN(T& x) {cin >> x;}
template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); }
 
// output
template<class T1, class T2> void OUT(const pair<T1,T2>& x);
template<class T> void OUT(const vector<T>& x);
template<class T> void OUT(const T& x) {cout << x;}
template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); }
template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);}
template<class T> void OUT(const vector<T>& x) {RE(i,x.size()) OUT(i==0?"":" ",x[i]);}
template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); }
template<class H> void OUTLS(const H& h) {OUTL(h); }
template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); }
 
// dp
template<class T> bool ckmin(T&a, T&b) { bool bl = a > b; a = min(a,b); return bl;}
template<class T> bool ckmax(T&a, T&b) { bool bl = a < b; a = max(a,b); return bl;}
 
void program();
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    program();
}
 

// mod library
ll MOD=1e9+7;

inline ll mod(ll x_) {
    return (x_)%MOD;
}
ll modpow(ll x_, ll N_) {
    if(N_ == 0) return 1;
    ll a = modpow(x_,N_/2);
    a = (a*a)%MOD;
    if(N_%2) a = (a*x_)%MOD;
    return a;
}
ll inv(ll x_) {
    return modpow(x_, MOD-2);
}
class mi {
public:
    mi(ll v=0) {value = v;}
    mi  operator+ (ll rs) {return mod(value+rs);}
    mi  operator- (ll rs) {return mod(value-rs+MOD);}
    mi  operator* (ll rs) {return mod(value*rs);}
    mi  operator/ (ll rs) {return mod(value*inv(rs));}
    mi& operator+=(ll rs) {*this = (*this)+rs; return *this;}
    mi& operator-=(ll rs) {*this = (*this)-rs; return *this;}
    mi& operator*=(ll rs) {*this = (*this)*rs; return *this;}
    mi& operator/=(ll rs) {*this = (*this)/rs; return *this;}
    operator ll&() {return value;}

    ll value;
};
typedef vector<mi> vmi;

//===================//
//   begin program   //
//===================//
 
const int MX = 5e5;
const int N = (1<<20);

int n, a[MX];
int m, b[MX];
int lis[MX];

// fenwick tree
int FT[MX];
void addFT(int i, int value) {
    for(i++; i<=n; i+=i&-i) FT[i] = max(FT[i],value);
}
int getFT(int i) {
    int ans = 0;
    for(i++; i; i-=i&-i) ans = max(ans,FT[i]);
    return ans;
}
void addSM(int i, mi value) {
    for(i++; i<MX; i+=i&-i) FT[i] = (mi)FT[i] + value;
}
mi getSM(int i) {
    mi ans = 0;
    for(i++; i; i-=i&-i) ans += (mi)FT[i];
    return ans;
}

vi layer[MX];
int c[MX], dpi[MX], dpe[MX];

void program() {
    IN(n);
    RE(i,n) IN(a[i]);
    REV(i,1,n) b[m++] = a[i];
    RE(i,n) b[m++] = a[i];

    // fill c
    RE(i,m) c[i] = 1;
    c[m/2] = mi(1)/mi(2);

    // coördinate compression
    vi difa;
    RE(i,n) difa.pb(a[i]);
    sort(all(difa));
    RE(i,n) a[i] = lower_bound(all(difa),a[i]) - difa.begin();
    RE(i,m) b[i] = lower_bound(all(difa),b[i]) - difa.begin();

    // finding lis
    RE(i,m) {
        lis[i] = getFT(b[i]-1)+1;
        addFT(b[i],lis[i]);
    }
    RE(i,m) layer[lis[i]].pb(i);

    RE(i,MX) FT[i] = 0;

    RE1(i,n) {
        vi pq;
        FOR(j,layer[i-1])
            pq.pb(j);
        FOR(j,layer[i])
            pq.pb(j);
        sort(all(pq));
        FOR(j,pq) {
            if(lis[j] == i) {
                dpe[j] = (mi)c[j]*getSM(b[j]-1);
                if(i == 1) dpe[j] = c[j];
                if(j == m/2) {
                    dpi[j] = dpe[j];
                    dpe[j] = 0;
                }
            } else {
                addSM(b[j],dpe[j]);
            }
        }
        FOR(j,layer[i-1]) addSM(b[j],-dpe[j]);
    }

    RE1(i,n) {
        vi pq;
        FOR(j,layer[i-1])
            pq.pb(j);
        FOR(j,layer[i])
            pq.pb(j);
        sort(all(pq));
        FOR(j,pq) {
            if(lis[j] == i) {
                if(j == m/2) continue;
                dpi[j] = (mi)c[j]*getSM(b[j]-1);
            } else {
                addSM(b[j],dpi[j]);
            }
        }
        FOR(j,layer[i-1]) addSM(b[j],-dpi[j]);
    }

    int ans=0;
    RE(i,m) ans = max(ans,lis[i]);

    mi res1=0;
    RE(i,m) if(lis[i] == ans) res1 += (mi)dpi[i];
    res1 *= modpow(2,n-ans+1);
    mi res2=0;
    RE(i,m) if(lis[i] == ans) res2 += (mi)dpe[i];
    res2 *= modpow(2,n-ans-1);
    res1 += res2;

    OUTLS(ans,(ll)res1);
}

• Subtask 1: 140 / 140