제출 #417672

#제출 시각아이디문제언어결과실행 시간메모리
417672MarcoMeijerHedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++14
100 / 100
2833 ms104276 KiB
#include <bits/stdc++.h> using namespace std; // macros typedef long long ll; typedef long double ld; typedef pair<int, int> ii; typedef pair<ll, ll> lll; typedef tuple<int, int, int> iii; typedef vector<int> vi; typedef vector<ii> vii; typedef vector<iii> viii; typedef vector<ll> vll; typedef vector<lll> vlll; #define REP(a,b,c) for(int a=int(b); a<int(c); a++) #define RE(a,c) REP(a,0,c) #define RE1(a,c) REP(a,1,c+1) #define REI(a,b,c) REP(a,b,c+1) #define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--) #define FOR(a,b) for(auto& a : b) #define all(a) a.begin(), a.end() #define INF 1e18 #define EPS 1e-9 #define pb push_back #define popb pop_back #define fi first #define se second mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); // input template<class T> void IN(T& x) {cin >> x;} template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); } // output template<class T1, class T2> void OUT(const pair<T1,T2>& x); template<class T> void OUT(const vector<T>& x); template<class T> void OUT(const T& x) {cout << x;} template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); } template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);} template<class T> void OUT(const vector<T>& x) {RE(i,x.size()) OUT(i==0?"":" ",x[i]);} template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); } template<class H> void OUTLS(const H& h) {OUTL(h); } template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); } // dp template<class T> bool ckmin(T&a, T&b) { bool bl = a > b; a = min(a,b); return bl;} template<class T> bool ckmax(T&a, T&b) { bool bl = a < b; a = max(a,b); return bl;} void program(); int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); program(); } //===================// // begin program // //===================// const int MX = 1e6+10; const int N = (1<<20); int n, m; int w[MX]; int l[MX], r[MX], k[MX]; // fenwick tree int ft[MX]; void addFT(int x, int v) { for(x++; x>0; x-=x&-x) ft[x] = max(ft[x], v); } int getFT(int x) { int res = 0; for(x++; x<MX; x+=x&-x) res = max(res,ft[x]); return res; } // queries int a[MX]; vi qend[MX]; int ans[MX]; void program() { IN(n,m); RE1(i,n) IN(w[i]); RE(i,m) IN(l[i],r[i],k[i]); RE(i,m) qend [r[i]].pb(i); vi stck; RE1(i,n) { int lowest = stck.empty() ? -1 : a[stck.back()]; int ed = i; while(!stck.empty() && a[stck.back()] <= w[i]) { int u = stck.back(); stck.pop_back(); if(a[u] != lowest && lowest != -1) addFT(ed-1,a[u] + lowest); ed = u; lowest = max(lowest, a[u]); } stck.pb(ed); a[ed] = w[i]; FOR(j,qend[i]) { int res = getFT(l[j]); auto it = upper_bound(all(stck),l[j]); it--; auto it2 = it; it2++; if(it2 != stck.end()) res = max(res, a[*it] + a[*it2]); ans[j] = res <= k[j]; } } RE(i,m) cout<<ans[i]<<endl; }
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