제출 #417653

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
417653		usachevd0	Rectangles (IOI19_rect)	C++17	25 / 100	5035 ms	31704 KiB

rect

#include <bits/stdc++.h>
#ifndef LOCAL
    #include "rect.h"
#endif

using namespace std;

#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define all(a) (a).begin(), (a).end()
#define Time (clock() * 1.0 / CLOCKS_PER_SEC)
using ll = long long;
using ull = unsigned long long;
using pii = pair<int, int>;
using pil = pair<int, ll>;
using pli = pair<ll, int>;
using pll = pair<ll, ll>;
using ld = long double;
template<typename T1, typename T2> bool chkmin(T1& x, T2 y) {
    return y < x ? (x = y, true) : false;
}
template<typename T1, typename T2> bool chkmax(T1& x, T2 y) {
    return y > x ? (x = y, true) : false;
}
void debug_out() {
    cerr << endl;
}
template<typename T1, typename... T2> void debug_out(T1 A, T2... B) {
    cerr << ' ' << A;
    debug_out(B...);
}
template<typename T> void mdebug_out(T* a, int n) {
    for (int i = 0; i < n; ++i)
        cerr << a[i] << ' ';
    cerr << endl;
}
#ifdef LOCAL
    #define debug(...) cerr << "[" << #__VA_ARGS__ << "]:", debug_out(__VA_ARGS__)
    #define mdebug(a, n) cerr << #a << ": ", mdebug_out(a, n)
#else
    #define debug(...) 1337
    #define mdebug(a, n) 1337
#endif
template<typename T> ostream& operator << (ostream& stream, const vector<T>& v) {
    for (auto& x : v)
        stream << x << ' ';
    return stream;
}
template<typename T1, typename T2> ostream& operator << (ostream& stream, const pair<T1, T2>& p) {
    return stream << p.first << ' ' << p.second;
}

const int INF32 = 1e9;
const int maxN = 2503;
bool badc[maxN];
int L[maxN], R[maxN];
int stk[maxN][maxN], sz[maxN];

ll count_rectangles(vector<vector<int>> a) {
    int n = a.size(), m = a[0].size();
    if (min(n, m) < 3) return 0;
    ll ans = 0;
    for (int r1 = 1; r1 < n - 1; ++r1) {
        for (int r2 = r1; r2 < n - 1; ++r2) {
            badc[0] = badc[m - 1] = 1;
            for (int c = 1; c < m - 1; ++c) {
                int mx = -INF32;
                for (int i = r1; i <= r2; ++i)
                    chkmax(mx, a[i][c]);
                badc[c] = mx >= min(a[r1 - 1][c], a[r2 + 1][c]);
            }
            // count L
            for (int r = r1; r <= r2; ++r) {
                sz[r] = 0;
            }
            for (int c = 0; c < m; ++c) {
                L[c] = -1;
                for (int r = r1; r <= r2; ++r) {
                    while (sz[r] && a[r][stk[r][sz[r] - 1]] < a[r][c]) {
                        --sz[r];
                    }
                    if (sz[r])
                        chkmax(L[c], stk[r][sz[r] - 1]);
                    stk[r][sz[r]++] = c;
                }
            }
            // count R
            for (int r = r1; r <= r2; ++r) {
                sz[r] = 0;
            }
            for (int c = m - 1; c >= 0; --c) {
                R[c] = m;
                for (int r = r1; r <= r2; ++r) {
                    while (sz[r] && a[r][stk[r][sz[r] - 1]] < a[r][c]) {
                        --sz[r];
                    }
                    if (sz[r])
                        chkmin(R[c], stk[r][sz[r] - 1]);
                    stk[r][sz[r]++] = c;
                }
            }
            
            int b = m - 1;
            for (int c = m - 2; c >= 0; --c) {
                for (int d = c + 2; d <= min(b, R[c]); ++d) {
                    ans += L[d] <= c;
                }
                if (badc[c]) {
                    b = c;
                }
            }
        }
    }
    return ans;
}


#ifdef LOCAL


int main() {
#ifdef LOCAL
    freopen("in", "r", stdin);
#endif
    // InputReader inputReader(STDIN_FILENO);
    int n, m;
    cin >> n >> m;
    // n = inputReader.readInt();
    // m = inputReader.readInt();
    vector<vector<int>> a(n, vector<int>(m));
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++) {
            cin >> a[i][j];
            // a[i][j] = inputReader.readInt();
        }
    }
    // inputReader.close();

    long long result = count_rectangles(a);

    printf("%lld\n", result);
    fclose(stdout);
    return 0;
}
#endif

• Subtask 1: 8 / 8
• Subtask 2: 7 / 7
• Subtask 3: 0 / 12
• Subtask 4: 0 / 22
• Subtask 5: 10 / 10
• Subtask 6: 0 / 13
• Subtask 7: 0 / 28