이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "tickets.h"
#include <bits/stdc++.h>
using namespace std;
#define FOR(i, a, b) for (int i = (a); i <= (b); i++)
#define REP(n) FOR(O, 1, (n))
#define f first
#define s second
typedef long long ll;
//int mxLeft[1600];
//int mxCnt[1600];
//int mnTaken[1600];
int mn[1600], mx[1600];
long long find_maximum(int k, std::vector<std::vector<int>> x) {
int n = x.size();
int m = x[0].size();
std::vector<std::vector<int>> answer;
ll sum = 0;
priority_queue<pair<ll, pair<int, int>>> q;
for (int i = 0; i < n; i++) {
std::vector<int> row(m);
for (int j = 0; j < m; j++) {
if (j >= m-k) {
//row[j] = m-j-1;
row[j] = -1;
sum += x[i][j];
//mxLeft[i]++;
//mxCnt[i]++;
mx[i]++;
} else {
row[j] = -1;
}
}
answer.push_back(row);
q.push({- x[i][0] - x[i][m-k], {i, 0}});
}
REP(n*k/2) {
auto p = q.top();
q.pop();
ll val = p.f;
int i = p.s.f;
int j = p.s.s;
sum += val;
mx[i]--;
mn[i]++;
//mxLeft[i]--;
//mxCnt[i]--;
// answer[i][j] = k-j-1;
// answer[i][m-k+j] = -1;
if (j < k-1) {
j++;
q.push({- x[i][j] - x[i][m-k+j], {i,j}});
}
}
int mnId = 0;
FOR(i, 0, n-1) {
int cur = mnId;
FOR(j, 0, mn[i]-1) {
answer[i][j] = cur;
cur = (cur+1)%k;
}
FOR(j, m-mx[i], m-1) {
answer[i][j] = cur;
cur = (cur+1)%k;
}
mnId = (mnId + mn[i]) % k;
}
allocate_tickets(answer);
return sum;
}
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