제출 #41620

#제출 시각아이디문제언어결과실행 시간메모리
41620funcsr구슬과 끈 (APIO14_beads)C++14
100 / 100
396 ms28648 KiB
#include <iostream> #include <vector> #include <string> #include <algorithm> #include <cassert> using namespace std; #define int long long typedef pair<int, int> P; #define rep(i, n) for (int i=0; i<(n); i++) #define all(x) x.begin(), x.end() #define uniq(x) x.erase(unique(all(x)), x.end()) #define index(x, y) (int)(lower_bound(all(x), y) - x.begin()) #define _1 first #define _2 second #define pb push_back //#define INF 2100000000 #define INF (1LL<<40) int N; vector<P> G[200000]; P dp[200000][3]; void update(int x, int v, int s) { if (P(v, s) > dp[x][1]) dp[x][2] = dp[x][1], dp[x][1] = P(v, s); else if (P(v, s) > dp[x][2]) dp[x][2] = P(v, s); } int get(int x, int s=-2) { return dp[x][1+(dp[x][1]._2==s)]._1; } void dfs(int x, int p) { dp[x][0] = P(0, -1); dp[x][1] = P(-INF, -1); dp[x][2] = P(-INF, -1); for (P pp : G[x]) if (pp._1 != p) { int t = pp._1, len = pp._2; dfs(t, x); int v = max(dp[t][0]._1, dp[t][1]._1+len); dp[x][0]._1 += v; } for (P pp : G[x]) if (pp._1 != p) { int t = pp._1, len = pp._2; int v = max(dp[t][0]._1, dp[t][1]._1+len); update(x, dp[x][0]._1-v + dp[t][0]._1+len, t); } } void dfs2(int x, int p, int plen, int diff) { if (p != -1) { int pv = max(plen + get(p, x) - diff, dp[p][0]._1 - diff); for (int k=1; k<=2; k++) if (dp[x][k]._1 != -INF) dp[x][k]._1 += pv; update(x, dp[x][0]._1 + plen + dp[p][0]._1 - diff, p); int old =dp[x][0]._1; dp[x][0]._1 += pv; } for (P pp : G[x]) if (pp._1 != p) { int t = pp._1, len = pp._2; dfs2(t, x, len, max(dp[t][0]._1, dp[t][1]._1+len)); } } signed main() { cin >> N; rep(i, N-1) { int a, b, c; cin >> a >> b >> c; a--, b--; G[a].pb(P(b, c)); G[b].pb(P(a, c)); } dfs(0, -1); dfs2(0, -1, 0, 0); int m = 0; rep(i, N) m = max(m, dp[i][0]._1); cout << m << "\n"; return 0; }

컴파일 시 표준 에러 (stderr) 메시지

beads.cpp: In function 'void dfs2(long long int, long long int, long long int, long long int)':
beads.cpp:50:9: warning: unused variable 'old' [-Wunused-variable]
     int old =dp[x][0]._1;
         ^~~
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