이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
const long long oo = 1LL << 60;
int n;
vector<pair<int, int>> a[100100];
long long f[2020];
long long g[2020]; // can keep parent edge
void visit(int x, int par, int k)
{
f[x] = 0;
vector<long long> gain;
for (auto [y, w] : a[x])
if (y != par)
{
visit(y, x, k);
f[x] += f[y] + w;
gain.push_back(g[y] - f[y] - w);
}
sort(gain.begin(), gain.end());
g[x] = f[x];
for (int i = 0; i < k && i < gain.size(); i++)
{
if (gain[i] >= 0)
break;
f[x] += gain[i];
if (i < k - 1)
g[x] += gain[i];
}
f[x] = min(f[x], g[x]);
}
vector<long long> minimum_closure_costs(int N, vector<int> U, vector<int> V, vector<int> W) {
n = N;
int isLine = 1;
for (int i = 0; i < n - 1; i++)
{
a[U[i]].push_back({V[i], W[i]});
a[V[i]].push_back({U[i], W[i]});
if (U[i] != i || V[i] != i + 1)
isLine = 0;
}
vector<long long> ans(n);
ans[0] = accumulate(W.begin(), W.end(), 0LL);
// 1
if (a[0].size() == n - 1)
{
sort(W.begin(), W.end(), greater<int>());
for (int i = n - 2; i >= 0; i--)
ans[i] = ans[i + 1] + W[i];
return ans;
}
// 2
if (isLine)
{
vector<long long> f(n, oo);
f[0] = 0;
f[1] = W[0];
for (int i = 2; i < n; i++)
f[i] = min(f[i - 1], f[i - 2]) + W[i - 1];
ans[1] = min(f[n - 1], f[n - 2]);
}
if (n <= 2000)
{
for (int i = 1; i < n - 1; i++)
{
visit(0, -1, i);
ans[i] = f[0];
}
}
return ans;
}
컴파일 시 표준 에러 (stderr) 메시지
roads.cpp: In function 'void visit(int, int, int)':
roads.cpp:24:30: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
24 | for (int i = 0; i < k && i < gain.size(); i++)
| ~~^~~~~~~~~~~~~
roads.cpp: In function 'std::vector<long long int> minimum_closure_costs(int, std::vector<int>, std::vector<int>, std::vector<int>)':
roads.cpp:49:19: warning: comparison of integer expressions of different signedness: 'std::vector<std::pair<int, int> >::size_type' {aka 'long unsigned int'} and 'int' [-Wsign-compare]
49 | if (a[0].size() == n - 1)
| ~~~~~~~~~~~~^~~~~~~~
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