제출 #415102

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
415102		meatrow	Lottery (CEOI18_lot)	C++17	35 / 100	504 ms	4556 KiB

lot

// #pragma GCC target ("avx2")
#pragma GCC optimization ("O3")
#include <bits/stdc++.h>

using namespace std;

using ll = long long;
using ld = long double;

const int MOD = 1e9 + 7;

ll binpow(ll a, ll p, int mod = MOD) {
    ll res = 1;
    while (p) {
        if (p & 1) {
            (res *= a) %= mod;
        }
        p >>= 1;
        (a *= a) %= mod;
    }
    return res;
}

ll gcd(ll a, ll b) {
    return b == 0 ? a : gcd(b, a % b);
}

const int N = 10005;
const int Q = 105;

int a[N], id[N];
int ans[N][Q];

void solve() {
    int n, l;
    cin >> n >> l;
    for (int i = 0; i < n; i++) {
        cin >> a[i];
    }
    int q;
    cin >> q;
    vector<pair<int, int>> queries(q);
    for (int i = 0; i < q; i++) {
        cin >> queries[i].first;
        queries[i].second = i;
    }
    sort(queries.begin(), queries.end());
    queries.push_back({1e9, q});
    int cur = 0;
    for (int i = 0; i <= l; i++) {
        id[i] = cur;
        if (i == queries[cur].first) {
            cur++;
        }
    }

    for (int i = 1; i <= n - l; i++) {
        // [0, i] -> [1, i + 1]
        int dist = 0;
        for (int pos = 0; pos < l; pos++) {
            dist += a[pos] != a[i + pos];
        }
        ans[0][id[dist]]++;
        ans[i][id[dist]]++;
        for (int j = i + 1; j <= n - l; j++) {
            dist += a[l + j - i - 1] != a[l + j - 1];
            dist -= a[j - i - 1] != a[j - 1];
            ans[j - i][id[dist]]++;
            ans[j][id[dist]]++;
        }
    }

    for (int i = 0; i < n; i++) {
        for (int j = 1; j < q; j++) {
            ans[i][j] += ans[i][j - 1];
        }
    }

    sort(queries.begin(), queries.end(), [](const auto& f, const auto& s) {
        return f.second < s.second;
    });
    for (int i = 0; i < q; i++) {
        for (int j = 0; j <= n - l; j++) {
            cout << ans[j][i] << " \n"[j == n - l];
        }
    }
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int T = 1;
    // cin >> T;
    for (int tc = 1; tc <= T; tc++) {
        // cout << "Case #" << tc << ": ";
        solve();
    }
    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

lot.cpp:2: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
    2 | #pragma GCC optimization ("O3")
      |

• Subtask 1: 0 / 25
• Subtask 2: 0 / 20
• Subtask 3: 20 / 20
• Subtask 4: 15 / 15
• Subtask 5: 0 / 20