Submission #414976

#	Time	Username	Problem	Language	Result	Execution time	Memory
414976		cfalas	Mechanical Doll (IOI18_doll)	C++14	53 / 100	228 ms	14628 KiB

doll

#include "doll.h"
#include<bits/stdc++.h>
using namespace std;
#define mp make_pair
#define INF 10000000
#define MOD 1000000007
#define MID ((l+r)/2)
#define HASHMOD 2305843009213693951
#define ll long long
#define ull unsigned long long
#define F first
#define S second
typedef pair<ll, ll> ii;
typedef pair<ii, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef map<int, int> mii;

#define EPS 1e-6
#define FOR(i,n) for(int i=0;i<((int)(n));i++)
#define FORi(i,a,b) for(int i=((int)(a));i<((int)(b));i++)
#define FOA(v, a) for(auto v : a)

int s=0, n;
vector<vi> nxt;
vector<int> C, X, Y;

int b;
int inv(int x){
	vi a;
	//cout<<x<<" ";
	FOR(i,b) a.push_back(x%2), x/=2;
	ll ans=0;
	FOA(v,a) ans*=2, ans+=v;
	//cout<<ans<<endl;
	return ans;
}

void rec(int x, int l, int r){
	//cout<<x<<": "<<l<<" "<<r<<endl;
	if(l==r) return;
	if(r==l+1){
		if(inv(l)<(int)nxt[x].size()-1) X.push_back(nxt[x][inv(l)]);
		else if(l==(1<<b)-1) X.push_back(nxt[x].back());
		else X.push_back(C[x]);
		
		l++;
		if(inv(l)<(int)nxt[x].size()-1) Y.push_back(nxt[x][inv(l)]);
		else if(l==(1<<b)-1) Y.push_back(nxt[x].back());
		else Y.push_back(C[x]);
	}
	else{
		X.push_back(-(++s));
		int q = Y.size();
		Y.push_back(s);
		rec(x, l, MID);
		Y[q] = -(++s);
		rec(x, MID+1,r);
	}
}

void create_circuit(int M, std::vector<int> A) {
	n = A.size();
	nxt.assign(M+1, vi());
	C.assign(M+1, 0);
	nxt[0].push_back(A[0]);
	FORi(i,1,n) nxt[A[i-1]].push_back(A[i]);
	nxt[A[n-1]].push_back(0);
	FOR(x,M+1){
		int q = nxt[x].size();
		if(q==0) continue;
		else if(q==1) C[x] = nxt[x][0];
		else{
			int t = q-1;

			int l=0;
			while(t) l++, t/=2;
			b = l;
			//cout<<q<<": "<<b<<endl;

			C[x] = -(++s);
			rec(x, 0, (1<<l)-1);
		}
	}
#ifdef LOCAL
	FOA(v,C) cout<<v<<" ";
	cout<<endl;
	FOA(v,X) cout<<v<<" ";
	cout<<endl;
	FOA(v,Y) cout<<v<<" ";
	cout<<endl;
#endif

	answer(C, X, Y);
}

• Subtask 1: 2 / 2
• Subtask 2: 4 / 4
• Subtask 3: 10 / 10
• Subtask 4: 0 / 10
• Subtask 5: 9.0000000036 / 18
• Subtask 6: 28.0000000112 / 56