Submission #413602

#	Time	Username	Problem	Language	Result	Execution time	Memory
413602		jamezzz	Tents (JOI18_tents)	C++14	48 / 100	2081 ms	64476 KiB

tents

#include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
#include <ext/rope>
using namespace __gnu_cxx;

typedef tree<long long, null_type, less<long long>,
rb_tree_tag, tree_order_statistics_node_update> pbds;
//less_equal for identical elements

//#define DEBUG

#ifdef DEBUG
#define debug(...) printf(__VA_ARGS__);
#else
#define debug(...)
#endif
#define sf scanf
#define pf printf
#define fi first
#define se second
#define pb emplace_back
#define sz(x) (int)x.size()
#define mnto(x,y) x=min(x,(__typeof__(x))y)
#define mxto(x,y) x=max(x,(__typeof__(x))y)
#define INF 1023456789
#define LINF 1023456789123456789
#define all(x) x.begin(), x.end()
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
typedef tuple<int, int, int, int> iiii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<pll> vll;

#define mod 1000000007

int h,w;
ll dp[2][3005][3005];

int main(){
	sf("%d%d",&h,&w);
	if(h>w)swap(h,w);
	int t=0;
	for(int i=0;i<=h;++i){
		for(int j=0;j<=h;++j)dp[1-t][i][j]=1;
	}
	for(int c=w;c>=1;--c){
		for(int f=0;f<=h;++f){
			for(int u=0;u+f<=h;++u){
				if(c!=w||f!=h)dp[t][f][u]=dp[1-t][f][u];
				if(f>=2)dp[t][f][u]+=dp[1-t][f-2][u]*f*(f-1)/2,dp[t][f][u]%=mod;
				if(u>=1)dp[t][f][u]+=dp[1-t][f][u-1]*u,dp[t][f][u]%=mod;
				if(f>0)dp[t][f][u]+=3*f*dp[1-t][f-1][u]+f*dp[1-t][f-1][u+1],dp[t][f][u]%=mod;
			}
		}
		//pf("%lld %lld\n",dp[t][1][0],dp[t][0][1]);
		t=1-t;
	}
	pf("%lld\n",dp[1-t][h][0]);
}

Compilation message (stderr)

tents.cpp: In function 'int main()':
tents.cpp:47:4: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   47 |  sf("%d%d",&h,&w);
      |    ^

• Subtask 1: 48 / 48
• Subtask 2: 0 / 52