제출 #413458

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
413458		egorlifar	Robot (JOI21_ho_t4)	C++17	100 / 100	1660 ms	114756 KiB

Main

/*
KAMUI!
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*/
#include <iostream>
#include <complex>
#include <vector>
#include <string>
#include <algorithm>
#include <cstdio>
#include <numeric>
#include <cstring>
#include <ctime>
#include <cstdlib>
#include <set>
#include <map>
#include <unordered_map>
#include <unordered_set>
#include <list>
#include <cmath>
#include <bitset>
#include <cassert>
#include <queue>
#include <stack>
#include <deque>
#include <random>
#include <array>
 
using namespace std;
template<typename T1, typename T2> inline void chkmin(T1 &a, T2 b) {if (a > b) a = b;}
template<typename T1, typename T2> inline void chkmax(T1 &a, T2 b) {if (a < b) a = b;}
#define files(FILENAME) read(FILENAME); write(FILENAME)
#define read(FILENAME) freopen((FILENAME + ".in").c_str(), "r", stdin)
#define write(FILENAME) freopen((FILENAME + ".out").c_str(), "w", stdout)
#define all(c) (c).begin(), (c).end()
#define sz(c) (int)(c).size()
#define left left228
#define right right228
#define y1 y1228
#define mp make_pair
#define pb push_back
#define y2 y2228
#define rank rank228
using ll = long long;
using ld = long double; 
const string FILENAME = "input";


const int MAXN = 200229;
const ll LLINF = 3e18;


int N, M;
map<int, vector<pair<int, int> > > edge[MAXN];
int color[MAXN];
int cost[MAXN];
map<int, ll> sum[MAXN];
//you can only save it if its color is unique or its color is twice and you just used one of them & paid.
ll dist[MAXN];
map<int, ll> special[MAXN];
priority_queue<array<ll, 3>, vector<array<ll, 3> >, greater<array<ll, 3> > > pq;
ll ans;


void solve() {
    cin >> N >> M;
    for (int i = 0; i < M; i++) { 
        int u, v, c, d;
        cin >> u >> v >> c >> d; u--; v--;
        edge[u][c].pb({v, i});
        edge[v][c].pb({u, i});
        sum[u][c] += d;
        sum[v][c] += d;
        color[i] = c;
        cost[i] = d;
    }
    for (int u = 0; u < N; u++)
    {
        for (auto &p : edge[u])
        {
            sort(all(p.second), [&](pair<int, int> a, pair<int, int> b)
            {
                return cost[a.second] > cost[b.second];
            });
        }
    }
    fill(dist, dist + N, LLINF);
    dist[0] = 0;
    pq.push({0, 0, -1});
    while(!pq.empty())
    {
        ll d = pq.top()[0]; int u = pq.top()[1], c = pq.top()[2];
        pq.pop();
        if (c != -1)
        {
            if (d != special[u][c]) continue;
            int cl = color[c];
            int it = 0;
            for (auto e : edge[u][cl])
            {
                int v = e.first, eid = e.second; ll dis = cost[eid];
                ll nd = d + min(dis, sum[u][cl] - dis - cost[c]);
                if (dist[v] > nd)
                {
                    dist[v] = nd;
                    pq.push({nd, v, -1});
                }
                it++;
                if (it > 3) break;
            }
        }
        else
        {
            if (d != dist[u]) continue;
            for (auto p : edge[u])
            {
                int cl = p.first;
                for (auto e : p.second)
                {
                    int v = e.first, eid = e.second; ll dis = cost[eid];
                    ll nd = d + min(dis, sum[u][cl] - dis);
                    if (dist[v] > nd)
                    {
                        dist[v] = nd;
                        pq.push({nd, v, -1});
                    }
                    nd = d + dis;
                    if ((special[v].find(eid) == special[v].end() || special[v][eid] > nd))
                    {
                        special[v][eid] = nd;
                        pq.push({nd, v, eid});
                    }
                }
            }
        }
    }
    ans = dist[N - 1];
    if (ans >= LLINF) ans = -1;
    cout << ans << '\n';
}
//21:50

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
   // read(FILENAME);
    int t;
    t = 1;
  //  cin >> t;
    while (t--) {
        solve();
    }
    return 0;
}
 

• Subtask 1: 34 / 34
• Subtask 2: 24 / 24
• Subtask 3: 42 / 42