제출 #412869

#제출 시각아이디문제언어결과실행 시간메모리
412869losmi247Paint By Numbers (IOI16_paint)C++14
32 / 100
1 ms332 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 2e5+45; const int K = 105; int n,k; string s; int c[K]; int pf[N],suf[N]; string prazna(){ int sum = 0; for(int i = 1; i <= k; i++) sum += c[i]; if(sum == n-(k-1)){ string ans = ""; for(int i = 1; i <= k; i++){ for(int j = 1; j <= c[i]; j++) ans += 'X'; if(i < k) ans += '_'; } return ans; } for(int i = 1; i <= k; i++) pf[i] = pf[i-1]+c[i]; for(int i = k; i >= 1; i--) suf[i] = suf[i+1]+c[i]; string ans = s; for(int i = 0; i < n; i++){ /// da li moze da bude X na i? bool mozex = 0; for(int j = 1; j <= k; j++){ for(int poc = max(0,i-c[j]+1); poc <= i && poc+c[j]-1 < n; poc++){ if(pf[j-1]+(j-1) <= poc && suf[j+1]+(k-(j+1)+1) <= n-poc-1) mozex = 1; } } /// da li moze da bude _ na i? bool mozey = 0; if(k == 1) mozey = (i <= n-1-c[1] || i >= c[1]); for(int j = 1; j < k; j++){ if(pf[j]+(j-1) <= i && suf[j+1]+(k-(j+1)) <= n-i-1) mozey = 1; } mozey |= (i <= n-(sum+k-1)-1 || i >= sum+k-1); if(mozex && mozey) ans[i] = '?'; else if(mozex) ans[i] = 'X'; else if(mozey) ans[i] = '_'; } return ans; } bool pfdp[K][N],sfdp[K][N]; string novo(){ int sum = 0; for(int i = 1; i <= k; i++) sum += c[i]; if(sum == n-(k-1)){ string ans = ""; for(int i = 1; i <= k; i++){ for(int j = 1; j <= c[i]; j++) ans += 'X'; if(i < k) ans += '_'; } return ans; } for(int i = 1; i <= k; i++) pf[i] = pf[i-1]+c[i]; for(int i = k; i >= 1; i--) suf[i] = suf[i+1]+c[i]; for(int i = 0; i <= n; i++) pfdp[0][i] = 1; for(int j = 1; j <= k; j++){ for(int i = 1; i <= n; i++){ pfdp[j][i] |= pfdp[j][i-1]; /// stavi _ na i if(i < c[j]) continue; bool moze = 1; for(int h = i-c[j]+1; h <= i; h++){ /// stavi j-ti blok tako da se zavrsava na i if(s[h-1] == '_') moze = 0; } pfdp[j][i] |= (moze && pfdp[j-1][i-c[j]]); } } for(int i = n+1; i >= 1; i--) sfdp[k+1][i] = 1; for(int j = k; j >= 1; j--){ for(int i = n; i >= 1; i--){ sfdp[j][i] |= sfdp[j][i+1]; /// stavi _ na i if(n-i+1 < c[j]) continue; bool moze = 1; for(int h = i; h <= i+c[j]-1; h++){ if(s[h-1] == '_') moze = 0; } sfdp[j][i] |= (moze && sfdp[j+1][i+c[j]]); } } vector <int> bry(n+1,0); for(int i = 1; i <= n; i++) bry[i] = bry[i-1]+(s[i-1] == '_'); string ans = s; for(int i = 0; i < n; i++){ if(s[i] == '_'){ ans[i] = '_'; continue; } /// da li moze da bude X na i? bool mozex = 0; for(int j = 1; j <= k; j++){ for(int poc = max(0,i-c[j]+1); poc <= i && poc+c[j]-1 < n; poc++){ if(bry[poc+c[j]]-bry[poc] == 0 && pfdp[j-1][poc] && sfdp[j+1][poc+c[j]+1]) mozex = 1; } } /// da li moze da bude _ na i? bool mozey = 0; for(int j = 1; j < k; j++){ if(pfdp[j][i] && sfdp[j+1][i+2]) mozey = 1; } mozey |= pfdp[k][i]; mozey |= sfdp[1][i+2]; assert(mozex || mozey); if(mozex && mozey) ans[i] = '?'; else if(mozex) ans[i] = 'X'; else if(mozey) ans[i] = '_'; } return ans; } string solve_puzzle(string s1,vector <int> c1){ n = s1.size(); k = c1.size(); s = s1; for(int i = 1; i <= k; i++) c[i] = c1[i-1]; bool prz = 1,nemax = 1; for(auto f : s){ if(f != '.') prz = 0; if(f == 'X') nemax = 0; } if(n <= 100 && prz){ return prazna(); } if(n <= 100 && nemax){ return novo(); } }

컴파일 시 표준 에러 (stderr) 메시지

paint.cpp: In function 'std::string solve_puzzle(std::string, std::vector<int>)':
paint.cpp:152:1: warning: control reaches end of non-void function [-Wreturn-type]
  152 | }
      | ^
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