이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define fbo find_by_order
#define ook order_of_key
typedef long long ll;
typedef pair<ll,ll> ii;
typedef vector<int> vi;
typedef long double ld;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds;
typedef set<int>::iterator sit;
typedef map<int,int>::iterator mit;
typedef vector<int>::iterator vit;
vector<ii> adj[111111];
int n,m;
vector<ll> dijkstra(int s)
{
priority_queue<ii,vector<ii>,greater<ii> > pq;
vector<ll> d(n, ll(1e18));
pq.push(mp(0,s)); d[s] = 0;
while(!pq.empty())
{
ll dist=pq.top().fi; int u=pq.top().se; pq.pop();
for(ii x:adj[u])
{
ll d2 = dist + x.se;
if(d[x.fi] > d2)
{
d[x.fi] = d2;
pq.push(mp(d2, x.fi));
}
}
}
return d;
}
ll dp[111111];
ll dp2[111111];
ll dist[111111];
ll dist2[111111];
int main()
{
ios_base::sync_with_stdio(0); cin.tie(0);
cin>>n>>m;
int s,e,s2,e2; cin>>s>>e>>s2>>e2;
s--; e--; s2--; e2--;
for(int i=0;i<m;i++)
{
int u,v,c; cin>>u>>v>>c; u--; v--;
adj[u].pb(mp(v,c)); adj[v].pb(mp(u,c));
}
vector<ll> d1 = dijkstra(s2);
vector<ll> d2 = dijkstra(e2);
ll ans = d1[e2];
priority_queue<ii,vector<ii>,greater<ii> > pq;
for(int i=0;i<n;i++) dist[i]=dist2[i]=dp[i]=dp2[i]=ll(1e18);
dist[s] = 0; dp[s] = d2[s]; pq.push(mp(0,s));
while(!pq.empty())
{
ll d=pq.top().fi; int u=pq.top().se; pq.pop(); ll pre = dp[u];
for(ii x:adj[u])
{
ll dt = d + x.se; int v = x.fi;
if(dist[v] > dt)
{
dp[v] = min(pre, d2[v]);
dist[v] = dt;
pq.push(mp(dt,v));
}
else if(dist[v] == dt)
{
dp[v] = min(dp[v], min(pre, d2[v]));
}
}
}
dist2[e] = 0; dp2[e] = d2[e]; pq.push(mp(0,e));
while(!pq.empty())
{
ll d=pq.top().fi; int u=pq.top().se; pq.pop(); ll pre = dp2[u];
for(ii x:adj[u])
{
ll dt = d + x.se; int v = x.fi;
if(dist2[v] > dt)
{
dp2[v] = min(pre, d2[v]);
dist2[v] = dt;
pq.push(mp(dt,v));
}
else if(dist2[v] == dt)
{
dp2[v] = min(dp2[v], min(pre, d2[v]));
}
}
}
ll shortestori = dist[e];
for(int i=0;i<n;i++)
{
if(dist[i]+dist2[i]==shortestori)
{
ans = min(ans, min(dp[i], dp2[i]) + d1[i]);
}
}
cout<<ans<<'\n';
}
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