제출 #410233

#제출 시각아이디문제언어결과실행 시간메모리
410233jeqchoJakarta Skyscrapers (APIO15_skyscraper)C++17
57 / 100
1075 ms23740 KiB
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pair<int,int>> vpi;

#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)
#define trav(a,x) for (auto& a: x)

#define pb push_back
#define rsz resize
#define sz(x) int(x.size())
#define all(x) begin(x), end(x)
#define fi first
#define se second

struct triple
{
	int a,b,c;
};

bool operator<(const triple &x, const triple &y)
{
	return x.a<y.a;
}

int const N=3e4+3;
int const sN=170;
int const M=3e4+3;
int b[M];
int p[M];
int d[N][sN];
bitset<sN> vis[N];
int const INF=1e9;
vi doges[N];

int main()
{
	ios_base::sync_with_stdio(0); cin.tie(0);
	int n,m;
	cin>>n>>m;
	F0R(i,m)
	{
		cin>>b[i]>>p[i];
		doges[b[i]].pb(i);
	}
	F0R(i,n)
	{
		fill(d[i],d[i]+sN,INF);
	}
	priority_queue<triple> q;
	q.push({0,b[0],0});
	d[b[0]][0]=0;
	while(!q.empty())
	{
		int pos = q.top().b;
		int pw = q.top().c;
		q.pop();
		vector<triple>adj;
		int curd;
		if(pw>=sN)
		{
			int nxt=pos+pw;
			int cnt=1;
			while(nxt<n)
			{
				adj.pb({nxt,0,cnt});
				++cnt;
				nxt+=pw;
			}
			nxt=pos-pw;
			cnt=1;
			while(nxt>=0)
			{
				adj.pb({nxt,0,cnt});
				++cnt;
				nxt-=pw;
			}
			curd=d[pos][0];
		}
		else
		{
			if(vis[pos][pw])continue;
			vis[pos][pw]=1;
			curd = d[pos][pw];
			if(pw==0)
			{
				trav(doge,doges[pos])
				{
					if(p[doge]>=sN)
					{
						q.push({(int)1e9,pos,p[doge]});
					}
					else
					{
						adj.pb({pos,p[doge],0});
					}
				}
			}
			else
			{
				adj.pb({pos,0,0});
				int nxt = pos+pw;
				if(nxt<n)
				{
					adj.pb({nxt,pw,1});
				}
				nxt = pos-pw;
				if(nxt>=0)
				{
					adj.pb({nxt,pw,1});
				}
			}
		}
		trav(e,adj)
		{
			int cand = curd + e.c;
			if(cand<d[e.a][e.b])
			{
				d[e.a][e.b]=cand;
				q.push({-cand,e.a,e.b});
			}
		}
	}
	if(d[b[1]][0]==INF)
	{
		cout<<-1<<'\n';
	}
	else
	{
		cout<<d[b[1]][0]<<'\n';
	}
	return 0;
}
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