제출 #409027

#제출 시각아이디문제언어결과실행 시간메모리
409027balbitA Difficult(y) Choice (BOI21_books)C++14
100 / 100
3 ms256 KiB
#include "books.h" #include <bits/stdc++.h> using namespace std; #define ll long long #define int ll #define y1 zck_is_king #define pii pair<int, int> #define ull unsigned ll #define f first #define s second #define ALL(x) x.begin(),x.end() #define SZ(x) (int)x.size() #define SQ(x) (x)*(x) #define MN(a,b) a = min(a,(__typeof__(a))(b)) #define MX(a,b) a = max(a,(__typeof__(a))(b)) #define pb push_back #define REP(i,n) for (int i = 0; i<n; ++i) #define RREP(i,n) for (int i = n-1; i>=0; --i) #define REP1(i,n) for (int i = 1; i<=n; ++i) #define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end())))) #ifdef BALBIT #define IOS() #define bug(...) fprintf(stderr,"#%d (%s) = ",__LINE__,#__VA_ARGS__),_do(__VA_ARGS__); template<typename T> void _do(T &&x){cerr<<x<<endl;} template<typename T, typename ...S> void _do(T &&x, S &&...y){cerr<<x<<", ";_do(y...);} #else #define IOS() ios_base::sync_with_stdio(0);cin.tie(0); #define endl '\n' #define bug(...) #endif const int iinf = 1e9+10; const ll inf = 1e18; const ll mod = 1e9+7 ; void GG(){cout<<"0\n"; exit(0);} ll mpow(ll a, ll n, ll mo = mod){ // a^n % mod ll re=1; while (n>0){ if (n&1) re = re*a %mo; a = a*a %mo; n>>=1; } return re; } ll inv (ll b, ll mo = mod){ if (b==1) return b; return (mo-mo/b) * inv(mo%b,mo) % mo; } const int maxn = 1e5+5; //using namespace std; // // --- Sample implementation for the task books --- // // To compile this program with the sample grader, place: // books.h books_sample.cpp sample_grader.cpp // in a single folder and run: // g++ books_sample.cpp sample_grader.cpp // in this folder. // void solve(signed N, signed K, long long A, signed S) { // TODO implement this function ll sums = 0; vector<ll> ff(K+1); REP1(i,K-1) { sums += (ff[i] = skim(i)); } int l = K, r = N+1; while (l != r) { int mid = (l+r)/2; ll tmp = (mid > N ? inf : skim(mid)); if (tmp + sums >= A && tmp + sums <= 2*A) { // good! vector<signed> re; REP1(i,K-1) re.pb(i); re.pb(mid); answer(re); } if (tmp + sums > 2*A) { // bad r = mid; }else{ l = mid+1; } } if (l == K) impossible(); ll now = sums + skim(l-1); vector<signed> pos; REP1(i,K-1) pos.pb(i); pos.pb(l-1); int at = SZ(pos)-2; while (now < A && at >= 0) { pos[at] = pos[at+1]-1; now -= ff[at]; now += skim(pos[at]); --at; } assert(now <= 2*A); if (now < A) impossible(); answer(pos); }
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