제출 #408986

#제출 시각아이디문제언어결과실행 시간메모리
408986arwaeystoamnegArt Exhibition (JOI18_art)C++17
100 / 100
235 ms24772 KiB
// EXPLOSION! #define _CRT_SECURE_NO_WARNINGS #include<bits/stdc++.h> #include<unordered_set> #include<unordered_map> #include<chrono> using namespace std; typedef pair<int, int> pii; typedef long long ll; typedef pair<ll, ll> pll; typedef long double ld; typedef vector<int> vi; typedef vector<ll> vll; typedef vector<pair<int, int>> vpi; typedef vector<pair<ll, ll>> vpll; #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define F0R(i,a) FOR(i,0,a) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) #define R0F(i,a) ROF(i,0,a) #define trav(a,x) for (auto& a: x) #define pb push_back #define mp make_pair #define rsz resize #define sz(x) int(x.size()) #define all(x) x.begin(),x.end() #define f first #define s second #define cont continue #define endl '\n' //#define ednl '\n' #define test int testc;cin>>testc;while(testc--) #define pr(a, b) trav(x,a)cerr << x << b; cerr << endl; #define message cout << "Hello World" << endl; const int dx[4] = { 1,0,-1,0 }, dy[4] = { 0,1,0,-1 }; // for every grid problem!! const ll linf = 4000000000000000000LL; const ll inf = 1000000007;//998244353 void pv(vi a) { trav(x, a)cout << x << " "; cout << endl; }void pv(vll a) { trav(x, a)cout << x << " "; cout << endl; }void pv(vector<vi>a) { F0R(i, sz(a)) { cout << i << endl; pv(a[i]); cout << endl; } }void pv(vector<vll>a) { F0R(i, sz(a)) { cout << i << endl; pv(a[i]); }cout << endl; }void pv(vector<string>a) { trav(x, a)cout << x << endl; cout << endl; } void setIO(string s) { ios_base::sync_with_stdio(0); cin.tie(0); #ifdef arwaeystoamneg if (sz(s)) { freopen((s + ".in").c_str(), "r", stdin); if (s != "test1") freopen((s + ".out").c_str(), "w", stdout); } #endif } const int MAX = 500005; int n, b[MAX], order[MAX]; ll a[MAX], prefix[MAX]; int main() { setIO("test1"); cin >> n; F0R(i, n)cin >> a[i] >> b[i]; iota(order, order + n, 0); sort(order, order + n, [](int i, int j) {return a[i] < a[j]; }); F0R(i, n)prefix[i + 1] = prefix[i] + b[order[i]]; ll best = linf; ll ans = -linf; F0R(i, n) { best = min(best, prefix[i] - a[order[i]]); ans = max(ans, prefix[i + 1] - a[order[i]] - best); } cout << ans << endl; }
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