제출 #406612

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
406612		nikolapesic2802	새로운 문제 (POI11_pio)	C++14	82 / 100	237 ms	11200 KiB

pio

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>

#define ll long long
#define pb push_back
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ios ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ld long double
#define li __int128

using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; ///find_by_order(),order_of_key()
template<int D, typename T>struct vec : public vector<vec<D - 1, T>> {template<typename... Args>vec(int n = 0, Args... args) : vector<vec<D - 1, T>>(n, vec<D - 1, T>(args...)) {}};
template<typename T>struct vec<1, T> : public vector<T> {vec(int n = 0, T val = T()) : vector<T>(n, val) {}};
template<class T1,class T2> ostream& operator<<(ostream& os, const pair<T1,T2>& a) { os << '{' << a.f << ", " << a.s << '}'; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const deque<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T1,class T2> ostream& operator<<(ostream& os, const map<T1,T2>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
int ri(){int x;scanf("%i",&x);return x;}
void rd(int&x){scanf("%i",&x);}
void rd(long long&x){scanf("%lld",&x);}
void rd(double&x){scanf("%lf",&x);}
void rd(long double&x){scanf("%Lf",&x);}
void rd(string&x){cin>>x;}
void rd(char*x){scanf("%s",x);}
template<typename T1,typename T2>void rd(pair<T1,T2>&x){rd(x.first);rd(x.second);}
template<typename T>void rd(vector<T>&x){for(T&p:x)rd(p);}
template<typename C,typename...T>void rd(C&a,T&...args){rd(a);rd(args...);}
//istream& operator>>(istream& is,__int128& a){string s;is>>s;a=0;int i=0;bool neg=false;if(s[0]=='-')neg=true,i++;for(;i<s.size();i++)a=a*10+s[i]-'0';if(neg)a*=-1;return is;}
//ostream& operator<<(ostream& os,__int128 a){bool neg=false;if(a<0)neg=true,a*=-1;ll high=(a/(__int128)1e18);ll low=(a-(__int128)1e18*high);string res;if(neg)res+='-';if(high>0){res+=to_string(high);string temp=to_string(low);res+=string(18-temp.size(),'0');res+=temp;}else res+=to_string(low);os<<res;return os;}

const int N=5e5+5;

int intersect(pair<int,int> a,pair<int,int> b){ //h,i
	assert(a.f<b.f&&a.s<b.s);
	int dist=b.s-a.s;
	int diff=b.f-a.f;
	int l=0,r=5*N;
	while(l<r){
		int m=(l+r)>>1;
		if(sqrt(m+dist)-sqrt(m)<=diff){
			r=m;
		}
		else{
			l=m+1;
		}
	}
	return min(N,l+b.s);
}
int findP(int hj,int hi,int inddiff){
	return ceil(hj-hi+sqrt(inddiff));
}
int main()
{
	int n=ri();
	vector<int> h(n);
	rd(h);
	vector<int> l(n),r(n);
	for(int k=0;k<2;k++){
		deque<pair<int,int>> cand;
		cand.pb({h[0],0});
		for(int i=1;i<n;i++){
			while(cand.size()>1&&intersect(cand[0],cand[1])<=i)
				cand.pop_front();
			l[i]=findP(cand[0].f,h[i],i-cand[0].s);
			if(h[i]>cand.back().f){
				while(cand.size()>1&&intersect(cand[cand.size()-1],{h[i],i})<=intersect(cand[cand.size()-2],cand[cand.size()-1])){
					assert(intersect(cand[cand.size()-2],cand[cand.size()-1])>i);
					cand.pop_back();
				}
				cand.push_back({h[i],i});
			}
		}
		reverse(all(h));
		swap(l,r);
	}
	reverse(all(r));
	for(int i=0;i<n;i++)
		printf("%i\n",max(l[i],r[i]));
	return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

pio.cpp: In function 'int ri()':
pio.cpp:33:21: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   33 | int ri(){int x;scanf("%i",&x);return x;}
      |                ~~~~~^~~~~~~~~
pio.cpp: In function 'void rd(int&)':
pio.cpp:34:21: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   34 | void rd(int&x){scanf("%i",&x);}
      |                ~~~~~^~~~~~~~~
pio.cpp: In function 'void rd(long long int&)':
pio.cpp:35:27: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   35 | void rd(long long&x){scanf("%lld",&x);}
      |                      ~~~~~^~~~~~~~~~~
pio.cpp: In function 'void rd(double&)':
pio.cpp:36:24: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   36 | void rd(double&x){scanf("%lf",&x);}
      |                   ~~~~~^~~~~~~~~~
pio.cpp: In function 'void rd(long double&)':
pio.cpp:37:29: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   37 | void rd(long double&x){scanf("%Lf",&x);}
      |                        ~~~~~^~~~~~~~~~
pio.cpp: In function 'void rd(char*)':
pio.cpp:39:22: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   39 | void rd(char*x){scanf("%s",x);}
      |                 ~~~~~^~~~~~~~

• Subtask 1: 9 / 9
• Subtask 2: 9 / 9
• Subtask 3: 9 / 9
• Subtask 4: 0 / 9
• Subtask 5: 0 / 9
• Subtask 6: 9 / 9
• Subtask 7: 9 / 9
• Subtask 8: 9 / 9
• Subtask 9: 9 / 9
• Subtask 10: 9 / 9
• Subtask 11: 10 / 10