제출 #405877

#제출 시각아이디문제언어결과실행 시간메모리
405877ignaciocantaGlobal Warming (CEOI18_glo)C++14
100 / 100
68 ms4240 KiB
#include <bits/stdc++.h> using namespace std; //#include <ext/pb_ds/assoc_container.hpp> //using namespace __gnu_pbds; //template<class T> using Tree = tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>; using tint = long long; using ld = long double; #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define F0R(i,a) FOR(i,0,a) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) #define R0F(i,a) ROF(i,0,a) #define trav(a,x) for (auto& a: x) using pi = pair<int,int>; using pl = pair<tint,tint>; using vi = vector<int>; using vpi = vector<pi>; using vpl = vector<pl>; using vvi = vector<vi>; using vl = vector<tint>; using vb = vector<bool>; #define pb push_back #define pf push_front #define rsz resize #define all(x) begin(x), end(x) #define rall(x) x.rbegin(), x.rend() #define sz(x) (int)(x).size() #define ins insert #define f first #define s second #define mp make_pair #define DBG(x) cerr << #x << " = " << x << endl; const int MOD = 1e9+7; const int mod = 998244353; const int MX = 2e5+5; const tint INF = 1e18; const int inf = 2e9; const ld PI = acos(ld(-1)); const ld eps = 1e-5; const int dx[4] = {1, -1, 0, 0}; const int dy[4] = {0, 0, 1, -1}; template<class T> void remDup(vector<T> &v){ sort(all(v)); v.erase(unique(all(v)),end(v)); } template<class T> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } bool valid(int x, int y, int n, int m){ return (0<=x && x<n && 0<=y && y<m); } int cdiv(int a, int b) { return a/b+((a^b)>0&&a%b); } //redondea p arriba int fdiv(int a, int b) { return a/b-((a^b)<0&&a%b); } //redondea p abajo void NACHO(string name = ""){ ios_base::sync_with_stdio(0); cin.tie(0); if(sz(name)){ freopen((name+".in").c_str(), "r", stdin); freopen((name+".out").c_str(), "w", stdout); } } vi dp; int L[MX], a[MX]; int main(){ NACHO(); // primero, vemos que siempre te conviene restarle a un prefijo. // Luego, sea L_i la LIS que termina en i, y R_i la LIS que comienza en i // si le reste al prefijo [1;i]. La respuesta es max(L_i+R_i-1) // Calcular L_i es trivial. // Para calcular R_i, voy de atrás para adelante. // Si x = 5 // 10 8 9 10 2 // 5 8 9 10 2 // para poder correr el algoritmo de LIS, en vez de meter a[i] meto -a[i]. // -2 // -10 // -10 -9 -8 int n, d; cin >> n >> d; F0R(i, n){ int x; cin >> x; a[i] = x; auto ind = lower_bound(all(dp), x)-dp.begin(); if(ind == sz(dp)) dp.pb(x); else dp[ind] = x; L[i] = ind+1; } int ret = sz(dp); dp.clear(); R0F(i, n){ int R = lower_bound(all(dp), -a[i]+d)-dp.begin(); ckmax(ret, L[i]+R); int ind = lower_bound(all(dp), -a[i])-dp.begin(); if(ind == sz(dp)) dp.pb(-a[i]); else dp[ind] = -a[i]; } cout << ret << "\n"; }

컴파일 시 표준 에러 (stderr) 메시지

glo.cpp: In function 'void NACHO(std::string)':
glo.cpp:73:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   73 |         freopen((name+".in").c_str(), "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
glo.cpp:74:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   74 |         freopen((name+".out").c_str(), "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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